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Mathematics

2 answers:

madam [21]3 years ago

7 0

Answer:

Step-by-step explanation:

Nesterboy [21]3 years ago

5 0

Answer:

I think the answer is B.

Step-by-step explanation:

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On average, how much more is the total cost of owning a cat for 10 years than owning a small dog for 10 years?

KiRa [710]

Answer:

Its 960

Step-by-step explanation:

7 0

4 years ago

Anas wants to build a one-sample z interval with 85% confidence to estimate what proportion of users will click an advertisement

klasskru [66]

Answer:

See below

Step-by-step explanation:

Check One Sample Z-Interval Conditions

Simple Random Sample? √

np≥10? √

n(1-p)≥10? √

One-Sample Z-Interval Information

Formula --> $CI=\hat{p}\pm z^*\biggr(\sqrt{\frac{\hat{p}(1-\hat{p})}{n}}\biggr)$
Sample Proportion --> $\hat{p}=\frac{54}{250}=0.216$
Critical Value --> $z^*=1.4395$ (for a 85% confidence level)
Sample Size --> $n=250$
Margin of Error (MOE) --> $\sqrt{\frac{\hat{p}(1-\hat{p})}{n}}$

Problem 1

As stated previously, Anas should use the critical value $z^*=1.4395$ to construct the 85% confidence interval

Problem 2

Given our formula for the margin of error (MOE), the value is $MOE=\sqrt{\frac{\hat{p}(1-\hat{p})}{n}}=\sqrt{\frac{0.216(1-0.216)}{250}}\approx0.026$

Problem 3

The 85% confidence interval would be $CI=\hat{p}\pm z^*\biggr(\sqrt{\frac{\hat{p}(1-\hat{p})}{n}}\biggr)=CI=0.216\pm 1.4395(0.026)\appro=\{0.1786,0.2534\}$ , which means that we are 85% confident that the true proportion of people that clicked on the advertisement is between 0.1786 (~45 people) and 0.2534 (~63 people)

Problem 4

Increasing the sample size to $n=500$ is going to decrease the margin of error because it is a closer representation of the population, but, alas, requires more time, energy, and resources to observe.