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Genrish500 [490]

4 years ago

8

Solve for x. x +

ac3{1}{3}" align="absmiddle" class="latex-formula"> = $\frac{1}{2}8$

1 answer:

Luda [366]4 years ago

3 0

the answer is -5 very easy

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Solve:<br> 2x - 20<br> 3<br> - 2x (5 points)<br> a<br> -5 -3<br> a<br> 13

kow [346]

Answer:

Negative five and negative three

6 0

3 years ago

Help<br><br> (5a-3a^3)*(4a-1)

ivann1987 [24]

Answer:

$-12a^{4} + 3a^{3} + 20a^{2} -5a$

Step-by-step explanation:

$(5a-3a^{3} )$ • $(4a-1)$

Let's use FOIL (first, outer, inner, last) to solve this. We'll multiply the terms by one another in that fashion.

$20a^{2} - 5a - 12a^{4} + 3a^{3}$

Rearrange in decreasing exponents.

$-12a^{4} + 3a^{3} + 20a^{2} -5a$

3 0

3 years ago

What is the answer of 3x?

Fiesta28 [93]

Answer:

3x

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Choose the graph below that has an undefined slope.

Ronch [10]

Answer:

The correct option is A.

Step-by-step explanation:

The first line passing through the points (-6,2) and (-6,0).

The slope of a line is

$m=\frac{y_2-y_1}{x_2-x_1}$

The slope of first line is

$m_1=\frac{0-2}{-6-(-6)}=\infty$

The second line passing through the points (0,-4) and (-1,1). The slope of second line is

$m_2=\frac{1-(-4)}{-1-0}=-5$

The third line passing through the points (0,-6) and (2,-6). The slope of third line is

$m_3=\frac{-6-(-6)}{2-0}=0$

The fourth line passing through the points (0,6) and (-3,-7). The slope of fourth line is

$m_4=\frac{-7-6}{-3-0}=\frac{13}{3}$

Since the slope of a vertical line is infinity, Therefore option A is correct.

8 0

3 years ago

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Please ANSWER THE ANSWER HAS TO BE A INTEGER OR A DECIMAL.

Natali [406]

Answer: 4.3

Step-by-step explanation: To find the range you have to subtract the highest number by the lowest number. So you'd subtract 2.6 by -1.7. And since -1.7 is already a negative number, it would get turned into a positive.

5 0

3 years ago

Read 2 more answers