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bearhunter [10]
3 years ago
7

I need help with this math problem. I have a picture of the question.

Mathematics
1 answer:
Svetlanka [38]3 years ago
4 0

Formula for distance between two points is

d∧2=(x2-x1)∧2+(y2-y1)∧2 in our case (x1,y1)=(k,q) and (x2,y2)=(0,0)

d∧2=(0-k)∧2+(0-q)∧2= k∧2+q∧2 => d=√(k∧2+q∧2)

Good luck!!!

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Which equation can be used to find the value of x?
vlabodo [156]

Answer:

(4x-10)+62=180

Step-by-step explanation:

4x-72=180

4x=180+72

x=252/4

x=63°

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7Bx%2B7%7D%20%2B%5Cfrac%7B4%7D%7Bx-8%7D" id="TexFormula1" title="\frac{3}{x+7}
sattari [20]

{7x+4}/{x^2-x-56}

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6 0
2 years ago
If P is the midpoint of XY, XP = 8x - 2 and PY = 12x - 30, find the<br> value of x.
Arlecino [84]

Answer:

x=7

Step-by-step explanation:

<u>If P is the midpoint of XY, then XP = PY:</u>

  • 8x - 2 = 12x - 30
  • 12x -8x = 30 -2
  • 4x = 28
  • x= 28/4
  • x= 7
3 0
3 years ago
PLEASE HELP WILL MARK BRAINLIEST!!(plz show work too)
trapecia [35]

\huge \bf༆ Answer ༄

Let the capacity of bus be x students

And van be y students, now ;

From the given statements we get two equations ~

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:2x + 10y = 260 \:   \:  \:  \: \:  (1)

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:13x + 5y = 670 \:  \:  \:  \:  \: (2)

multiply the equation (2) with 2 [ it won't change the values ]

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:2x + 10y = 260 \: \:  \:  \:   \:  \:  \:  \:  \: (1)

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:26x + 10y = 1340 \:  \:  \:  \:  \: (3)

Now, deduct equation (1) from equation (3)

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:26x + 10y - 2x - 10y = 1340 - 260

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:24x = 1080

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:x = 1080 \div 24

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:x = 45

Therefore each bus can carry (x) = 45 students

Now, plug the value of x in equation (1) to find y ~

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:2x + 10y = 260

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:(2 \times 45) + 10y = 260

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:90 + 10y = 260

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:10y = 260 - 90

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:10y = 170

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:y = 170 \div 10

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:y = 17

Hence, each van can carry (y) = 17 students in total.

5 0
2 years ago
What multiplies to 16 and adds to negative 12
Romashka-Z-Leto [24]
Factor 16 and see the - factor pairs and add them, see which add to -12
-1-16=-17 nope
-2-8=-10 nope
-4-4=-8
hmm


we will solve with math
xy=16
x+y=-12
minus  x both sides
y=-12-x
sub for y in other equation
x(-12-x)=16
-12x-x^2=16
add 12x+x^2 both sides
0=x^2+12x+16
use quadratic formula
if you have
ax^2+bx+c=0
x=\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}


0=x^2+12x+16
a=1
b=12
c=16

x=\frac{-12+/- \sqrt{12^{2}-4(1)(16) }}{2(1)}
x=\frac{-12+/- \sqrt{144-64 }}{2}
x=\frac{-12+/- \sqrt{80}}{2}
x=\frac{-12+/- 4\sqrt{5}}{2}
x=\frac{-6+/- 2\sqrt{5}
x=\frac{-6+ 2\sqrt{5} or \frac{-6- 2\sqrt{5}

aprox
x=-1.52786 or -10.4721

those are the numbers

the numbes are -1.52786 or -10.4721

6 0
3 years ago
Read 2 more answers
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