The correct answer is 39.0
Answer:
34
Step-by-step explanation:
Order of Operations: BPEMDAS
Step 1: Write out equation
18 × 2 - 4² ÷ 8
Step 2: Exponents
18 × 2 - 16 ÷ 8
Step 3: Multiply
36 - 16 ÷ 8
Step 4: Divide
36 - 2
Step 5: Subtract
34
Answer:
The probability that 8 mice are required is 0.2428.
Step-by-step explanation:
Given : A scientist inoculates mice, one at a time, with a disease germ until he finds 3 that have contracted the disease. If the probability of contracting the disease is two sevenths.
To find : What is the probability that 8 mice are required? The probability that that 8 mice are required is nothing ?
Solution :
Applying binomial distribution,

Where, p is the probability of success 
q is the probability of failure q=1-p, 
n is total number of trials n=8
r=3
Substitute the values,




Therefore, the probability that 8 mice are required is 0.2428.
<span>2 and 3/4 punds of roast beef 2 3/4 = (4x2) + 3 /4= 11/4 roast beef
</span><span>1 and 7/8 pounds of turkey 1 7/8 = 15/8 </span>turkey
2 1/16 pounds of salami 2 1/16 33/16 <span>salami
</span><span>if you put 1/4 of pound of meat
</span>then 11/4 roast beef divided by 1/4 = 11/4 x4 = 11 sandwiches roast beef
15/8 turkey<span> divided 1/4 = 15/8 x 4 = 15/2 = 7 sandwishes
</span>
33/16 salami divided <span> 1/4 = 33/16 x 4 = 33/ 4 = 8 sandwiches</span>
(X)=2X-ALL real numbers except x=0x<_0