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Rudiy27
3 years ago
5

Given V = 1/3pi(r^2)h, solve for r.

Mathematics
1 answer:
Dmitry [639]3 years ago
8 0

Volume = (PI * r^2 * h) / 3

r^2 = (3 * Volume) / (PI * h)

r = Square Root (3 * Volume) / (PI * h)


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Drag a statement or reason to each box to compete this proof.
alexandr402 [8]

Answer:

The answers of the proof are the following:

2. Multiplication Property of Equality

3. x-2 = 8

4. Addition Property of Equality

5. x=10, Simplifying

8 0
3 years ago
Sam intends to roll a six sided cube 100 times. What is the probability model he can use to predict whether or not each roll wil
bekas [8.4K]

The outcomes of rolling fair six sided die is \{1,2,3,4,5,6\}. The prime numbers in the above outcomes are \{2,3,5\}. The probability of not rolling a prime number is p=\frac{3}{6}= 0.5.

Each trial is independent.

In the given experiment of 100 trials, the binomial probability model can be used to predict the number of occurrence of non-prime numbers (X). The probability mass function is

P(X=x)=C(100,x)p^x(1-p)^{100-x},x=0,1,2,3,...,100. Since p=0.5,1-p=0.5

P(X=x)=C(100,x)0.5^x(0.5)^{100-x},x=0,1,2,3,...,100 \\ P(X=x)=C(100,x)(0.5)^{100},x=0,1,2,3,...,100

8 0
3 years ago
Read 2 more answers
A jar has five red marbles and 10 blue ones if you were to pick a random marble without replacing it and then select another wha
Andrej [43]
I think the correct answer is 10/15.
4 0
3 years ago
Can someone please help me
Vlada [557]
>>>1/5 is the answer<<<
8 0
3 years ago
Solve by factorising<br><br><img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title="x^{2}" alt="x^{2}" align="abs
Paladinen [302]

Step-by-step explanation:

\underline{ \underline{ \text{Solving \: a \: quadratic \: equation \: by \: factorisation \: method}}} :

In this method , the second order of polynomial ax² + bx + c is factorised and expressed as the product of two linear factors. Then each linear factor is separately solved to get the required solutions of the equation by applying zero factor property. In zero factor property , if p•q = 0 , then either p = 0 or q = 0 . In other words , if the product of two numbers is 0 , then one or both of the numbers must be 0.

\underline{ \underline{ \text{Let's \: solve}}} :

\tt{ {x}^{2}  + 16x +  55 = 0}

Here , we have to find the two numbers that multiplies to 55 and adds to 16.

⤑ \tt{ {x}^{2}  + (11 + 5)x + 55 = 0}

⤑ \tt{ {x}^{2}  + 11x + 5x +  55 = 0}

⤑ \tt{x(x + 11) + 5(x + 11) = 0}

⤑ \tt{(x + 5)(x + 11) = 0}

Either :

\tt{x + 5 = 0 \: \:  \:  \:  \: \:  \:  \:  \:  \:  \:  \:  \: Or :  \:  \:  x + 11 = 0}

\sf{⟶ x  = 0 - 5} \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:    \:⟶  x =  0 - 11

\tt{⟶x =  - 5 } \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:     \:  \:⟶   x =  - 11

\red{ \boxed{ \boxed{ { \tt{Our \: final \: answer :  \boxed{ \underline{  \bold{ \tt{x  =  - 5 \: , - 11}}}}}}}}}

Hope I helped ! ♡

Have a wonderful day / night ! ツ

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6 0
3 years ago
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