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galina1969 [7]
3 years ago
10

Y=2x+5 and y-4x=-2 One solution? Infinitely solution or no solution?

Mathematics
1 answer:
Alenkinab [10]3 years ago
8 0

Answer:

Y = 2x+5 would be one solution.  Y-4x=02 would also have one solution!

Step-by-step explanation:

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Writing Algebraic Expressions the product of 3 and X
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Step-by-step explanation:

3 \times x

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2 years ago
Simplify. (-5.12) - (-4.7) (7.021)
aksik [14]
First, you should do the product first:
(-4.7)* (7.021)= -32.9987

Then, let's do the subtraction:
(-5.12)- (-32.9987)
= (-5.12)+ 32.9987
= 27.8787

Final answer: 27.8787

Hope this would help~
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4 years ago
an airplane is flying from montreal to vancouver. the wind is blowing from the west at 60km/h. the airplane flies at an airspeed
Dominik [7]
Refer to the diagram shown below.

In order for the airplane to maintain a heading of 65° west of north,  it actually heads at (65° +x) west of north at a speed of 750 km/h, to compensate for the wind blowing from west t east at 60 km/h.

The actual speed of the airplane relative to the ground is V km/h.

From geometry, obtain the triangle shown.
The speed of 750 km/h is opposite an angle of 155°, and the unknown angle x is opposite the wind speed of 60 km/h.

From the Law of Sines, obtain
\frac{sin(x)}{60}= \frac{sin(155^{o}}{750} \\ sin(x)= (\frac{60}{750})sin(155^{o})=0.0338
x=sin^{-1}0.0338=1.937^{o}

The heading that the pilot should take is 65 + 1.937 = 66.94° west of north.

The third angle of the triangle is 180 - (155 + 1.937) = 23.063°.
Use the Law of Sines to calculate V.
\frac{V}{sin(23.063^{o})}= \frac{750}{sin(155^{o})}
V=( \frac{sin(23.063)}{sin(155)} )750=695.21\,km/h

Answer:
The pilot heads approximately 67° (nearest integer) west of north.
The speed of the airplane relative to ground is 695.2 km/h (nearest tenth)

8 0
4 years ago
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