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3 years ago

If you divide a polynomial f(x) by the factor (x - 4), the remainder will be equal to f(-4).

Mathematics

1 answer:

Bess [88]3 years ago

8 0

Answer:

False

Step-by-step explanation:

Given

Polynomial: f(x)

Divisor: (x - 4)

Required

Determine the remainder

To determine the remainder, we have to equate x - 4 to 0

i.e.

$x - 4 = 0$

Add 4 to both sides

$x - 4+4 = 0+4$

$x = 0+4$

$x = 4$

Substitute 4 for x in f(x) to get the remainder.

So, f(x) becomes f(4)

The result of f(4) is the remainder f(x) when divided by x - 4

Hence, the statement is false.

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What is the side lenth of a cube that has a volume of 27

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The anwer is 3. The volume of a cube is lwh. 3 x 3 x 3 = 27

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3 years ago

Adam currently runs about 20 miles per week,aND he wants to increase his weekly mileage by 30% How many miles will Adam run per

mel-nik [20]

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3 years ago

United Airlines' flights from Denver to Seattle are on time 50 % of the time. Suppose 9 flights are randomly selected, and the n

Ivanshal [37]

Answer:

a) The probability that exactly 4 flights are on time is equal to 0.0313

b) The probability that at most 3 flights are on time is equal to 0.0293

c) The probability that at least 8 flights are on time is equal to 0.00586

Step-by-step explanation:

The question posted is incomplete. This is the complete question:

United Airlines' flights from Denver to Seattle are on time 50 % of the time. Suppose 9 flights are randomly selected, and the number on-time flights is recorded. Round answers to 3 significant figures.

a) The probability that exactly 4 flights are on time is =

b) The probability that at most 3 flights are on time is =

c)The probability that at least 8 flights are on time is =

<h2>Solution to the problem</h2>

a) Probability that exactly 4 flights are on time

Since there are two possible outcomes, being on time or not being on time, whose probabilities do not change, this is a binomial experiment.

The probability of success (being on time) is p = 0.5.

The probability of fail (note being on time) is q = 1 -p = 1 - 0.5 = 0.5.

You need to find the probability of exactly 4 success on 9 trials: X = 4, n = 9.

The general equation to find the probability of x success in n trials is:

$P(X=x)=_nC_x\cdot p^x\cdot (1-p)^{(n-x)}$

Where $_nC_x$ is the number of different combinations of x success in n trials.

$_nC_x=\frac{x!}{n!(n-x)!}$

Hence,

$P(X=4)=_9C_4\cdot (0.5)^4\cdot (0.5)^{5}$

$_9C_4=\frac{4!}{9!(9-4)!}=126$

$P(X=4)=126\cdot (0.5)^4\cdot (0.5)^{5}=0.03125$

b) Probability that at most 3 flights are on time

The probability that at most 3 flights are on time is equal to the probabiity that exactly 0 or exactly 1 or exactly 2 or exactly 3 are on time:

$P(X\leq 3)=P(X=0)+P(X=1)+P(X=2)+P(X=3)$

$P(X=0)=(0.5)^9=0.00195313$ . . . (the probability that all are not on time)

$P(X=1)=_9C_1(0.5)^1(0.5)^8=9(0.5)^1(0.5)^8=0.00390625$

$P(X=2)=_9C_2(0.5)^2(0.5)^7=36(0.5)^2(0.5)^7=0.0078125$

$P(X=3)= _9C_3(0.5)^3(0.5)^6=84(0.5)^3(0.5)^6=0.015625$

$P(X\leq 3)=0.00195313+0.00390625+0.0078125+0.015625=0.02929688\\\\ P(X\leq 3) \approx 0.0293$

c) Probability that at least 8 flights are on time 

That at least 8 flights are on time is the same that at most 1 is not on time.

That is, 1 or 0 flights are not on time.

Then, it is easier to change the successful event to not being on time, so I will change the name of the variable to Y.

$P(Y=0)=_0C_9(0.5)^0(0.5)^9=0.00195313\\ \\ P(Y=1)=_1C_9(0.5)^1(0.5)^8=0.0039065\\ \\ P(Y=0)+P(Y=1)=0.00585938\approx 0.00586$

6 0

3 years ago

How to write 12.375 in expanded form

posledela

Twelve and three hundred and seventy five thousandths.

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3 years ago

Read 2 more answers

HELP I NEED HELP FAST. ILL MARK YOU BRAINLIEST.

Romashka-Z-Leto [24]

She plays soccer and golf for a total of 125 minutes:

s + g = 125

She plays soccer 45 minutes more than she plays golf:

s = g + 45 this is for A

B= 40 minutes of golf everyday

C= Yes, because in fact, she plays 85 minutes of soccer everyday, and 85 is greater than 80, so yes she CAN play 80 minutes of soccer every day. Perhaps they meant possible to spend ONLY 80 minutes, then NO, that wouldn't be possible, because then by playing 45 minutes more soccer than golf, she wouldn't have played enough to have 125 total minutes of total play. Technically the way the question is worded, the answer is yes.

I hope this helps!

5 0

2 years ago