If this is a parabolic motion equation, then it is a negative parabola, which looks like a hill (instead of a positive parabola that opens like a cup). Your equation would be h(t)= -16t^2 + 20t +3. That's the equation for an initial velocity of 20 ft/s thrown from an initial height of 3 ft. And the -16t^2 is the antiderivative of the gravitational pull. Anyway, if you're looking for the maximum height and you don't know calculus, then you have to complete the square to get this into vertex form. The vertex will be the highest point on the graph, which is consequently also the max height of the ball. When you do this, you get a vertex of (5/8, 9.25). The 9.25 is the max height of the ball.
In general when a firm produces nothing it still has to pay for the fixed costs while the variable costs are zero
Answer:
(1.5,0)
(.5,0)
Step-by-step explanation:
Quadratic formula below
We first need to move everything to one side of the equation
4x²-8x+3=0
Then plug everything in
(8±√(-8²-4*4*3))/(2*4)
(8±√16)/8
To calculate the ± we need to do when where it's adding and then negative
we have
(8+4)/8=3/2
and hten
(8-4)/8=1/2
you can just split the figure in 2 separate figures and them add the areas:
area rec. 1:
3m×3m= 9m²
area rec. 2:
3m× (2m+3m)
= 3m×5m
=15m²
total area:
9m²+15m²= 24m²
Answer:
13.5
Step-by-step explanation:
c = 2πr
42.3 = 2(3.14)r
42.3 = 6.28r
6.74 = r
d = r + r
d = 6.74 + 6.74
d = 13.5
