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damaskus [11]
3 years ago
10

Answer for brainliest

Mathematics
1 answer:
Vikentia [17]3 years ago
3 0
The answer is c

25/5 is 5

So 5>4
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Find the inner product for (-8,2) (4.5,18) and state whether the vectors are perpendicular.
Anna71 [15]

Answer: 0; Yes

Step-by-step explanation:

-8 x 4.5 = -36

2 x 18 = 36

-36 + 36 = 0

since the product is zero, the vectors are perpendicular

3 0
3 years ago
What is 3.2 x 10^-8 expressed as a decimal?
aniked [119]

Answer:

3.2MULTIPLY10-8

Step-by-step explanation:BECUASE THERE IS A NEGATIVE SENSE AND WHEN YOU PRESS YOUR CALACULTAOR U WILL SEE IT TRY IT IF DONT UNDERSTAND LET ME KNOW AGAIN THANKS

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Fiesta28 [93]
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7 0
3 years ago
The lengths of pregnancies are normally distributed with a mean of days and a standard deviation of days. a. Find the probabilit
Alik [6]

Answer:

a) The probability of a pregnancy lasting X days or longer is given by 1 subtracted by the p-value of Z = \frac{X - \mu}{\sigma}, in which \mu is the mean and \sigma is the standard deviation.

b) We have to find X when Z has a p-value of \frac{a}{100}, and X is given by: X = \mu - Z\sigma, in which \mu is the mean and \sigma is the standard deviation.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

In this question:

Mean \mu, standard deviation \sigma

a. Find the probability of a pregnancy lasting X days or longer.

The probability of a pregnancy lasting X days or longer is given by 1 subtracted by the p-value of Z = \frac{X - \mu}{\sigma}, in which \mu is the mean and \sigma is the standard deviation.

b. If the length of pregnancy is in the lowest a​%, then the baby is premature. Find the length that separates premature babies from those who are not premature.

We have to find X when Z has a p-value of \frac{a}{100}, and X is given by: X = \mu - Z\sigma, in which \mu is the mean and \sigma is the standard deviation.

8 0
3 years ago
What is the total of a $12,50 item plus 6% sales tax
balandron [24]
It’s is 20,0000 but it think that’s wrong
6 0
3 years ago
Read 2 more answers
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