Answer:
Step-by-step explanation:
1. A car requires 22 litres of petrol to travel a distance of 259.6 km
what is the distance that the car can travel on 63 ltr of petrol
22ltr = 259.6km
63ltr=
cross multiply
{63 x 259.6}/22 = 16354.8/22 = 743.4 km
A car requires 22 litres of petrol to travel a distance of 259.6 km, it would require 63 ltr of petrol to travel 743.4km
2. To travel a distance of 2013.2 km
we would need to calculate the amount of fuel
A car requires 22 litres of petrol to travel a distance of 259.6 km
what amount of fuel would it require to travel 2013.2km
22ltr = 259.6km
xltr = 2013.2km
x is the value of petrol to cover 2013.2km
cross multiply
(2013.2 x 22)/259.6
44290.4/259.6 = 170.610169492≈170.6 ltr
A car requires 22 litres of petrol to travel a distance of 259.6 km, it would require 170.6 ltr of petrol to travel 2013.2km
if 1ltr is $1.99
170.6 ltr is (170.6 x 1.99)/1 = $339.494≈$339.5
The price of fuel consumed for 2013.2 km at 1 liter of petrol at $1.99 is $339.5
Multiply the first equation by -1
-3x-y=-4
2x+y=5
Add them up
-x=1
So x=-1
And y=7
So the first option is correct
Answer:
Exponential
Step-by-step explanation:
- Linear is a straight line no matter what.
- Quadratic lines makes a u or v shape that opens up, down, left, or right.
- Exponential is like a slanted 45° clockwise u and a bit stretched horizontally.
- Square root lines on a graph, looks more like a slanted L 90° clockwise.
- Inverse Variation would show its inverse, same as a mirror, it would be something similar to a hyperbola.
Hope This Helps!
Answer:
4k+11
Step-by-step explanation:
There you go. Happy to help.
Answer:
X= 9//
Step-by-step explanation:
abc = efg
ac + cd = eg + gh
9 + (x+2) = 6 + (2x-4)
9 - 6 = 2x-4 - (x+2)
3 = x - 6
3+6 = x
9 = x//
