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Elina [12.6K]
3 years ago
8

Which system of equations will yield the same solution to the system below?

Mathematics
1 answer:
dalvyx [7]3 years ago
5 0
The answer to the question is B
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PLASS<br><br><br> HELPPP<br><br><br><br> WILL GIVE BRAINLISTTT<br><br><br><br> DUE RN
scoray [572]

Answer:

The area of the rectangle is 0.0875  sq ft.

Step-by-step explanation:

Given that,

The length of the rectangle, L = 0.35 feet

The breadth of the rectangle, B = 1/4 feet

We need to find the area of the rectangle. The formula for the area of a rectangle is given by :

A = LB

Put all the values,

A=\dfrac{1}{4}\times 0.35\\\\A=0.0875\ ft^2

So, the area of the rectangle is 0.0875  sq feet.

4 0
3 years ago
Which equation has the same solution as
uysha [10]

no se sabe

Step-by-step explanation:

knwiowkwkwnwkkwmwnw w w.qosmsls.w

6 0
3 years ago
Please someone help me to prove this..​
Pachacha [2.7K]

Answer:  see proof below

<u>Step-by-step explanation:</u>

Use the following Sum to Product Identities:

\sin x+\sin y=2\sin \bigg(\dfrac{x+y}{2}\bigg)\cos \bigg(\dfrac{x-y}{2}\bigg)\\\\\\\sin x-\sin y=2\cos \bigg(\dfrac{x+y}{2}\bigg)\sin \bigg(\dfrac{x-y}{2}\bigg)\\\\\\\cos x+\cos y=2\cos \bigg(\dfrac{x+y}{2}\bigg)\cos \bigg(\dfrac{x-y}{2}\bigg)\\\\\\\cos x+\cos y=-2\sin \bigg(\dfrac{x+y}{2}\bigg)\sin \bigg(\dfrac{x-y}{2}\bigg)

<u>Proof LHS → RHS</u>

\text{LHS:}\qquad \qquad \qquad \dfrac{\sin 5-\sin 15+\sin 25 - \sin 35}{\cos 5-\cos 15- \cos 25 + \cos 35}

\text{Reqroup:}\qquad \qquad \qquad \dfrac{(\sin 25+\sin 5)-(\sin 35 + \sin 15)}{(\cos 35+\cos 5)-(\cos 25 + \cos 15)}

\text{Sum to Product:}\quad \dfrac{2\sin \bigg(\dfrac{25+5}{2}\bigg)\cos \bigg(\dfrac{25-5}{2}\bigg)-2\sin \bigg(\dfrac{35+15}{2}\bigg)\cos \bigg(\dfrac{35-15}{2}\bigg)}{2\cos \bigg(\dfrac{25+15}{2}\bigg)\cos \bigg(\dfrac{25-15}{2}\bigg)-2\cos \bigg(\dfrac{35+5}{2}\bigg)\cos \bigg(\dfrac{35-5}{2}\bigg)}\text{Simplify:}\qquad \qquad \dfrac{2\sin 15\cos 10-2\sin 25\cos 10}{2\cos 20\cos 15-2\cos 20\cos 5}

\text{Factor:}\qquad \qquad \dfrac{2\cos 10(\sin 15-\sin 25)}{2\cos 20(\cos 15-\cos 5)}

\text{Sum to Product:}\qquad \dfrac{\cos 10\bigg[2\cos \bigg(\dfrac{15+25}{2}\bigg)\sin \bigg(\dfrac{15-25}{2}\bigg)\bigg]}{\cos 20\bigg[-2\sin \bigg(\dfrac{15+5}{2}\bigg)\sin \bigg(\dfrac{15-5}{2}\bigg)\bigg]}

\text{Simplify:}\qquad \qquad \dfrac{\cos 10[2\cos 20\sin (-5)]}{\cos 20[-2\sin 10\sin 5]}\\\\\\.\qquad \qquad \qquad =\dfrac{-2\cos10 \cos 20 \sin 5}{-2\sin 10 \cos 20 \sin 5}\\\\\\.\qquad \qquad \qquad =\dfrac{\cos 10}{\sin 10}\\\\\\.\qquad \qquad \qquad =\cot 10

LHS = RHS:  cot 10 = cot 10   \checkmark

8 0
3 years ago
Q7)
alukav5142 [94]

Answer:

srry what do u mean?

Step-by-step explanation:

7 0
3 years ago
12 23 17 20 14 14 18 16 17 18 18 mean median mode round to the rarest tenth
Vaselesa [24]
The mean is the average. To find this, we add up all the numbers, then divide by the number of numbers there are.
12+23+17+20+14+14+18+16+17+18+18= 187
187/11=17
The mean is 17.

The median is the middle number. To find this, line up all the numbers, smallest to largest.
12, 14, 14, 16, 17, 17, 18, 18, 18, 20, 23
You then cross off numbers from both sides, until you have 1 number remaining.
Your median is 17.

The mode is the number that occurs most frequently.
Your mode is 18.

3 0
4 years ago
Read 2 more answers
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