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3 years ago

Help please thanks quick

Mathematics

1 answer:

andrew11 [14]3 years ago

6 0

Answer:

The last option has another result than the others.

Step-by-step explanation:

The first option answer is 7/2

The second option answer is 7/2

The third option answer is 7/2

The last option answer is 2/7

Hope it will help :)

You might be interested in

Can someone help me with this pls

goldfiish [28.3K]

Answer:

252

Step-by-step explanation:

To answer the equation, you first need to note that it asks for surface area.

To find surface area, you use an input formula, known as SA=2lw+2lh+2hw. 'H' stands for height, 'L' stands for length, and 'W' stands for width.

Since the current height is 12, the current length is 6, and the width is 3, you need to plug them into the equation.

SA=2(6)(3)+2(6)(12)+2(12)(3)

SA=252

Quick tip! It's tempting to just multiply them all at once, but using the power of distribution is vital to solving these equations.

6 0

3 years ago

Joan works on commission for a furniture store. She gets a base pay of $85 a day plus 6 percent of the

podryga [215]

Answer:

Correct expression: 85 + 0.06(t - 400)

Correct earnings: $91

Step-by-step explanation:

The expression Joan wrote is incorrect because instead, $85, she put $400 as her base salary. The correct expression would be 85 + 0.06(t - 400), where 85 is her base pay in dollars, and t - 400 represents her sales in dollars exceeding $400.

If Joan's sales were $500, she would not make $424.90, but

85 + 0.06(t - 400)

85 + 0.06(500 - 400)

85 + 0.06(100)

85 + 6

$91

Hope this helps.

Cheers,

Andy

7 0

3 years ago

Find the roots of h(t) = (139kt)^2 − 69t + 80

Sonbull [250]

Answer:

The positive value of $k$ will result in exactly one real root is approximately 0.028.

Step-by-step explanation:

Let $h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ , roots are those values of $t$ so that $h(t) = 0$ . That is:

$19321\cdot k^{2}\cdot t^{2}-69\cdot t + 80=0$ (1)

Roots are determined analytically by the Quadratic Formula:

$t = \frac{69\pm \sqrt{4761-6182720\cdot k^{2} }}{38642}$

$t = \frac{69}{38642} \pm \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$

The smaller root is $t = \frac{69}{38642} - \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ , and the larger root is $t = \frac{69}{38642} + \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ .

$h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ has one real root when $\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} = 0$ . Then, we solve the discriminant for $k$ :