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3 years ago

Trigonometry Trigonometric Functions Given: Sin θ = (2/3), Find: Cosec θ

Mathematics

1 answer:

rosijanka [135]3 years ago

8 0

Answer:

csc θ = (3/2)

Step-by-step explanation:

Cosecant is just the inverse of sine

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3 years ago

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For the following exercises, determine whether the functions are even, odd, or neither.

stealth61 [152]

Answer:

The solutions of the equation |2 x-3|=17

are x=10

and x=-7

Step-by-step explanation:

Given equations is |2 x-3|=17.

It is required to find out the values of x satisfying the given equation.

To find it out, use the fact that the solution of this type of equation is 2x-3=17.

Or 2x-3=-17 and simplify the equations using simple mathematical operations.

Step 1 of 2

Solve the equation 2x-3=17,

Add 3 on both sides of the equation 2x-3=17,

2x-3+3=17+3

2x=20

Divide by 2 on both sides of the equation 2x=20,

$\begin{aligned}&\frac{2 x}{2}=\frac{20}{2} \\&x=10\end{aligned}$

Step 2 of 2

Solve the equation 2x-3=-17,

Add 3 on both sides of the equation 2x-3=-17,

$2 x-3+3=-17+3$\\ $2 x=-14$

Divide by 2 on both sides of the equation 2x=-14,

$\begin{aligned}&\frac{2 x}{2}=\frac{-14}{2} \\&x=-7\end{aligned}$

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2 years ago

Find the positive value of x in the geometric sequence 7x-2,4x+4,3x

Goryan [66]

Hello,

Let's assume k the ratio.

$
 \left \{ {{3x=k*(4x+4)} \atop {4x+4=k*(7x-2)}} \right. \\\\
 \left \{ {{3x-4kx=4k} \atop {4x-7kx=-2k-4}} \right. \\\\
 \left \{ {{x(3-4k)=4k} \atop {x(4-7k)=-2k-4}} \right. \\\\
 \left \{ {{x=\dfrac{4k}{3-4k} \atop {x=\dfrac{-2k-4}{4-7k} \right. \\\\

\dfrac{4k}{3-4k}=\dfrac{-2k-4}{4-7k}\\\\

36k^2-6k-12=0\\
6k^2-k-2=0\\

\boxed{k= \dfrac{2}{3} \ or\ k= -\dfrac{1}{2}}\\\\

x=\dfrac{4*\dfrac{2}{3} }{3-4*\dfrac{2}{3} }=8\\
x=\dfrac{4*\dfrac{-1}{2} }{3-4*\dfrac{-1}{2} }=-\dfrac{2}{5}\\





$

$\boxed{x= 8 \ or\ x= -\dfrac{2}{5}}\\\\$

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3 years ago

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Answer:

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