When we have consecutive values, f(10), f(11), f(12), f(13), f(14), we can make a difference table to determine the degree of f as a polynomial. A quadratic will have a constant second difference:
x 10 11 12 13 14
f(x) 50 71 94 119 146
1st diff 21 23 25 27
2nd diff 2 2 2
We got a constant second difference, so f is a polynomial of degree two.
Answer: This function is quadratic
Answer:
$233.39
Step-by-step explanation:
Pants = $82, 2 Shirts = $53 * 2, Shoes = $120
Add all these values up to find the total cost of your order excluding tax.
82 + 53(2) + 120 = 308
Next find the price w/ tax. Multiply 308 by 8.25%, or 0.0825.
308 * 0.0825 = 25.41
Now you add the tax to the total value.
308 + 25.41 = 333.41
The total value including tax is $333.41. The online retailer is offering a 30% savings (discount), so multiply the total price including tax by 30% (0.30).
333.41 * 0.30 = 100.023
Now you subtract the discount from the total price.
333.41 - 100.023 = 233.38700
The question say the answer rounded to the nearest cent or hundredths, so your final answer is 233.39.
The final price of the clothing including all discounts and taxes is $233.39.
The correct answer for this question is this one: "<span>C. P(C | A) = 0.75, P(C)=0.75 the events are not independent."
</span><span>The statement that can be determined about events A and C from the table is that </span><span>P(C | A) = 0.75, P(C)=0.75 the events are not independent. Hope this helps answer your question.
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Tammy's sample may not be considered valid because, on the first hand, it is said that she only asked students from her " Math Class".
If she wants to have a survey to find out the favorite subject of the students at her school, she must conduct a survey involving all the students in her school, not just in her class. What she did is just subjective. She should use a tally listing the different subjects and compare the number of students per subject. This way, she can have an objective representation of the least liked subjects and the most liked subjects of the students on her school.
Illustrating her survey through statistics may be more reliable and valid because it shows frequencies in which she can calculate easily and accurately the percentage of the number of students per subject, in a more objective manner.
X+y=44
x=5/6y
x+y=44
5/6y+y=44
11/6y=44
11y=264
y=24
x=5/6y=(5/6)*24=20
Answers: numbers are 20, 24
