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Oksi-84 [34.3K]

4 years ago

8

How to solve this math question

2%7D%7B8%7D%20" id="TexFormula1" title="6 \frac{1}{3} \times 5 \frac{2}{8} " alt="6 \frac{1}{3} \times 5 \frac{2}{8} " align="absmiddle" class="latex-formula">

1 answer:

pashok25 [27]4 years ago

7 0

Change each mixed numeral into a fraction, and then multiply them together using the rule for multiplication of fractions.

$6 \dfrac{1}{3} \times 5 \dfrac{2}{8} =$

$= 6 \dfrac{1}{3} \times 5 \dfrac{1}{4}$

$= \dfrac{19}{3} \times \dfrac{21}{4}$

$= \dfrac{19 \times 21}{3 \times 4}$

$= \dfrac{19 \times 7 \times 3}{4 \times 3}$

$= \dfrac{19 \times 7}{4}$

$= \dfrac{133}{4}$

$= 33 \dfrac{1}{4}$

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A number x with an exponent of -n means

Lady_Fox [76]

Answer:

C) Take the reciprocal of x

Step-by-step explanation:

That's my answer

7 0

3 years ago

The cost of producing pots is the initial investment, $175, plus $3.50 in materials per pot. Therefore, the function C(p) = 175

Sauron [17]

C(p) = 175 + 3.5p
Substitute for p = 125
C(p) = 175 + 3.5(125)
C(p) = 175 + 437.5
C(p) = 612.5

So, your final answer is Six hundred twelve dollars and 5 cents.

Hope it helped.

4 0

4 years ago

Read 2 more answers

What is the value of q?

musickatia [10]

180 so the would be the third bubble.

3 0

4 years ago

Use lagrange multipliers to find the point on the plane x â 2y + 3z = 6 that is closest to the point (0, 2, 4).

Arisa [49]

The distance between a point $(x,y,z)$ on the given plane and the point (0, 2, 4) is

$\sqrt{f(x,y,z)}=\sqrt{x^2+(y-2)^2+(z-4)^2}$

but since $\sqrt{f(x,y,z)}$ and $f(x,y,z)$ share critical points, we can instead consider the problem of optimizing $f(x,y,z)$ subject to $x-2y+3z=6$ .

The Lagrangian is

$L(x,y,z,\lambda)=x^2+(y-2)^2+(z-4)^2+\lambda(x-2y+3z-6)$

with partial derivatives (set equal to 0)

$L_x=2x+\lambda=0\implies x=-\dfrac\lambda2$
$L_y=2(y-2)-2\lambda=0\implies y=2+\lambda$
$L_z=2(z-4)+3\lambda=0\implies z=4-\dfrac{3\lambda}2$
$L_\lambda=x-2y+3z-6=0\implies x-2y+3z=6$

Solve for $\lambda$ :

$x-2y+3z=-\dfrac\lambda2-2(2+\lambda)+3\left(4-\dfrac{3\lambda}2\right)=6$
$\implies2=7\lambda\implies\lambda=\dfrac27$

which gives the critical point

$x=-\dfrac17,y=\dfrac{16}7,z=\dfrac{25}7$

We can confirm that this is a minimum by checking the Hessian matrix of $f(x,y,z)$ :

$\mathbf H(x,y,z)=\begin{bmatrix}f_{xx}&f_{xy}&f_{xz}\\f_{yx}&f_{yy}&f_{yz}\\f_{zx}&f_{zy}&f_{zz}\end{bmatrix}=\begin{bmatrix}2&0&0\\0&2&0\\0&0&2\end{bmatrix}$

$\mathbf H$ is positive definite (we see its determinant and the determinants of its leading principal minors are positive), which indicates that there is a minimum at this critical point.

At this point, we get a distance from (0, 2, 4) of

$\sqrt{f\left(-\dfrac17,\dfrac{16}7,\dfrac{25}7\right)}=\sqrt{\dfrac27}$

8 0

3 years ago

(-2)^-6 x (-2)^6

Gala2k [10]

Answer:

I'm not sure but according to my knowledge when you raise a number less than zero it gives you a non-complete and also negative number so I think the right answer might be

-0.015625 or -1/64

and 64

I'm again repeating that I'm not sure.

3 0

3 years ago