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3 years ago

1/5x + 1/2 = 3 + 1/2x

Mathematics

1 answer:

lawyer [7]3 years ago

3 0

Answer:

X=-25/3

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

1/5x+1/2-1/2x=1/2x+3-1/2x

-3/10x+1/2=3

Step 3: Subtract 1/2 from both sides.

-3/10x+1/2-1/2=3-1/2

-3/10x=5/2

Step 4: Multiply both sides by 10/(-3).

(10/-3)*(-3/10)=(10/-3)*(5/2)

X=-25/3

Hope that helps :D

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I WILL GIVE YOU 20 POINTS AND THE BRAINLYEST

fiasKO [112]

Answer/Step-by-step explanation:

✍️Slope of the line using two points, (2, 2) and (6, 10),

$slope (m) = \frac{y_2 - y_1}{x_2 - x_1} = \frac{10 - 2}{6 - 2} = \frac{8}{4} = 2$

✍️To find the equation of the line in slope-intercept form, we need to find the y-intercept (b).

Substitute x = 2, y = 2, and m = 2 in y = mx + b, and solve for b.

2 = (2)(2) + b

2 = 4 + b

2 - 4 = b

-2 = b

b = -2

Substitute m = 2 and b = -2 in y = mx + b.

✅The equation would be:

$y = 2x + (-2)$

$y = 2x - 2$

✍️To find the value of a, plug in (a, 8) as (x, y) into the equation of the line.

$8 = 2(a) - 2$

$8 = 2a - 2$

Add 2 to both sides

$8 + 2 = 2a$

$10 = 2a$

Divide both sides by 2

$\frac{10}{2} = a$

$5 = a$

a = 5

✍️To find the value of b, plug in (4, b) as (x, y) into the equation of the line.

$b = 2(4) - 2$

$b = 8 - 2$

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3 years ago

Dave and mary depart from the bus station at 10 am traveling in opposite directions. dave's bus is going 40 miles per hour and m

Montano1993 [528]

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3 years ago

There are 10 balls in a bag numbered from 1 to 10. Three balls are selected at random without replacement.

VikaD [51]

Answer:

A=1000

B=3.33

Step-by-step explanation:

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2 years ago

What is the equation of a circle whose center at (-5, -2) and radius is 2?

aliya0001 [1]

The equation of a circle whose centre ( $-5,-2$ ) and radius $2$ is $x^{2}+y^{2}+10x+4y+25=0$

What is equation of a circle?

A circle is a closed curve drawn from a fixed point called centre of the circle. The distance between the centre of the circle and the arc of the circle is called the radius of the circle.

The equation of a circle with centre $(h, k)$ radius $r$ is

$(x-h)^{2} +(y-k)^{2}=r^{2}$

Given center = $(-5,-2)$ and Radius = $2$

Put the Given value in the equation:

= $(x-(-5))^{2} +(y-(-2))^{2} = 2^{2}$

= $(x+5)^{2} +(y+2)^{2}=2^{2}$

= $(x^{2} +10x+25)+(y^{2}+4y+4)= 4$

= $x^{2} +y^{2}+10x+ 4y+ 29 = 4$

= $x^{2} +y^{2}+10x +4y+ 29-4=0$

= $x^{2} +y^{2}+10x+4y+25=0$

So, the equation of the circle whose centre is $(-5,-2)$ and Radius $2$ is

$x^{2}+y^{2}+10x+4y+25=0$

To read more about the equation of a circle. you can follow:

brainly.com/question/351704

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6 0

1 year ago

F(x) = 3x2 – x + 5; g(x) = 2x – 3. find f(x)-g(x)

Sonbull [250]

Answer:

f(x) - g(x) = 3x² - 3x + 8

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Distributive Property

Algebra I

Terms/Coefficients

Step-by-step explanation:

Step 1: Define

Identify

f(x) = 3x² - x + 5

g(x) = 2x - 3

Step 2: Find f(x) - g(x)

Substitute in function values: f(x) - g(x) = 3x² - x + 5 - (2x - 3)
[Distributive Property] Distribute negative: f(x) - g(x) = 3x² - x + 5 - 2x + 3
[Subtraction] Combine like terms (x): f(x) - g(x) = 3x² - 3x + 5 + 3
[Addition] Combine like terms: f(x) - g(x) = 3x² - 3x + 8

8 0

2 years ago

1/5x + 1/2 = 3 + 1/2x​

1/5x + 1/2 = 3 + 1/2x