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Tasya [4]
3 years ago
12

What is the value of -9 1/5 - 10 + 2/5 + 2(14 1/2 - 7)?​

Mathematics
1 answer:
Art [367]3 years ago
7 0

Answer:

-9 1/5 - 10 + 2/5 + 2(14 1/2 - 7) = -3.8

Step-by-step explanation:

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Nicola is multiplying 1/6 by 3/2<br> Use the drop-down menu to complete the statement
Over [174]
Greater than
1/6 x 3/2 = 1/4
1/4 > 1/6
5 0
3 years ago
Jared has 12 more comic books than Zoe. If they have 28 comic books
ZanzabumX [31]

Answer:

20 comic books

Step-by-step explanation:

Let us first <u>set up a variable</u>, x, for the number of books that Zoe has. If Jared has 12 more comics than Zoe, he would have x+12 books.

Given that Zoe and Jared have a total of 28 comic books, let us write an <u>equation</u> and solve for x:

x+x+12=28\\2x+12=28

Now that we have a <u>simplified</u> version of the equation, let us solve for x by <u>isolating the variable</u> on the left side:

2x=28-12\\2x=16\\x=8

We now know that x=8, and also that Jared has x+12 books. To find the number of comic books Jared has, let us <u>add</u> 12 to x:

x+12=\\8+12=\\20\\

Therefore, Jared has 20 comic books.

<em>I hope this helps! Please let me know if you have any further questions :)</em>

4 0
3 years ago
Ian wants to paint a wall measuring 3 metres by 7 metres.
anygoal [31]

Answer: 5.2

Step-by-step explanation:

3*7 = 21

21/5 = 4.2

4 0
3 years ago
Consider a large shipment of 400 refrigerators, of which 40 have defective compressors. If X is the number among 15 randomly sel
Vlad [161]

Answer:

The required probability is 0.94

Step-by-step explanation:

Consider the provided information.

There are 400 refrigerators, of which 40 have defective compressors.

Therefore N = 400 and X = 40

The probability of defective compressors is:

\frac{40}{400}=0.10

It is given that If X is the number among 15 randomly selected refrigerators that have defective compressors,

That means n=15

Apply the probability density function.

P(X=x)=^nC_xp^x(1-p)^{n-x}

We need to find P(X ≤ 3)

P(X\leq3) =P(X=0)+P(X=1)+P(X=2)+P(X=3)\\P(X\leq3) =\frac{15!}{15!}(0.1)^0(1-0.1)^{15}+\frac{15!}{14!}(0.1)^1(1-0.1)^{14}+\frac{15!}{13!2!}(0.1)^2(1-0.1)^{13}+\frac{15!}{12!3!}(0.1)^3(1-0.1)^{12}\\

P(X\leq3) =0.944444369992\approx 0.94

Hence, the required probability is 0.94

4 0
3 years ago
What are some study habits that helped? I have tried loads of ideas but I just can't to seem to find one that works for me.
Leviafan [203]
For me being 100% honest:

grade 9-11 no homework, pay attention in class and study night before.

Grade 12: pay attention more in class, do some homework when concepts hard, study night before.

Uni: Read notes, do class homework, read textbook, study week before.
7 0
4 years ago
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