If a,b,c are the 3 positive integers
1/a +1/b +1/c > 6/abc
(bc+ac+ab)/abc >6/abc so
(bc+ac+ab)>6
The lowest positive integers that are different are 1,2,3 so the lowest value that (bc+ac+ab) could have is 1•2+2•3+1•3=2+6+3= 11 therefore
1/a +1/b +1/c > 6/abc is true
Answer:
Step-by-step explanation:
I dont know if its right but I think you have to subtract 30% from seven since the equation is not being specific and I came up with 4.9 but dont quote me on it im just giving a educational guess
A I believe please let me know
Answer:
$1,080 please mark brainliest if satisfied
Step-by-step explanation:
1200 times 0.1 equals 120
1200 minus 120 equals 1080
4.07 * 100 = 407%
407 / 100 = 4.07