Please consider the attached file.
We can see that triangle JKM is a right triangle, with right angle at M. Segment KM is 6 units and segment MJ is 3 units. We can also see that KJ is hypotenuse of right triangle.
We will use Pythagoras theorem to solve for KJ as:




Now we will take positive square root on both sides:



Therefore, the length of line segment KJ is
and option D is the correct choice.
Answer:
the bottom left one
Step-by-step explanation:
This might not be correct but....
I’m going to use rounding,
42 x 2 = 84
84 divides by 3 = 28,
Which is near 30......So the number of people in the group is rounding to about 2 people.
Answer: roughly 4.2593
Step-by-step explanation:
920/216
put the equation through a calculator
approx. 4.2593
Answer:
Color Widegts
Widetsmith
Shortcuts + add shortcut (to change the icon) I think
Step-by-step explanation: