Answer:
f(x) has three real roots and two imaginary roots.
Step-by-step explanation:
Given that three roots of a fifth degree polynomial function f(x) are -2,2 and (4+i).
Now we need to find about which of the given statements describes the number and nature of all roots for this function.
We know that imaginary roots always occur in conjugate pairs.
So if (4+i) is root then (4-i) must also be the root.
So now we have total 4 roots
-2, 2, (4+i) and (4-i).
Degree of the polynomial is 5 so that means 1 root is still remaining. It can't be imaginary as that must be in pairs
So that means 5th root is real.
Hence correct choice is :
f(x) has three real roots and two imaginary roots.
No, it is not true
Lets do an example:
4 divided by 2 divided by 1 equals 2, while 2 divided by 1 divided by 4 equals 0.5
So you have to subtract 115 from 15. Then you divide that number by 5 for each relative. That should give you your answer....$20
Answer:
1031 Meters
Step-by-step explanation:
You would use the Pythagorean Theorem to solve it which would be a^2 + b^2 = c^2 and a would be 800 and b would be 650 in this circumstance you would try to find C which would be glenn blvd.
Answer:
Step-by-step explanation:
The average value theorem sets:
if f (x) is continuous in [a, b] and derivable in (a, b) there is a c Є (a, b) such that
, where
f(a)=f(π/2)=-4*sin(π/2) = -4*1= -4
f(b)=(3π/2)=-4*sin(3π/2) = -4*-1 = 4
⇒
c≅130
