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3 years ago

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A kite is flying at the end of a 20-meter string. If the string makes an angle of 55° with the ground, how many meters above the

ground, to the nearest meter, is the kite

1 answer:

Mama L [17]3 years ago

8 0

Answer:

Step-by-step explanation:

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An isosceles triangle has two sides of equal length, a, and a base, b. The perimeter of the triangle is 15.7 inches, so the equa

Orlov [11]

it cant be a negative number or zero

so now you are left with 0.5, 2 and 7.9

15.7 - 0.5 = 15.2 ( 15.2/2 = 7.6) this is possible

15.7 - 2 = 13.7 ( 13.7/2 = 6.85) this is possible

15.7 - 7.9 = 7.8 ( 7.8/2 = 3.9) (7.9/2 = 3.95) since the sides would be shorter than half the base this is not possible to form a triangle

so b can be either 0.5 or 2

Please mark brainliest

4 0

3 years ago

Read 2 more answers

(5,12) with a slope m=10 the equation of the line is

motikmotik

Answer:

y= 10x-38

Step-by-step explanation:

Equation of a line is usually written in the form of y=mx+c, where m is its gradient and c is its y-intercept.

Given that m=10,

y= 10x +c

Now substitute the coordinates into the equation.

When y=12, x=5,

12= 10(5) +c

12= 50 +c

c= 12 -50

c= -38

Thus the equation of the line is y= 10x -38

8 0

3 years ago

Help me, please!!!!!!!

navik [9.2K]

9514 1404 393

Answer:

2

Step-by-step explanation:

Alex has 10 money units. Annie has 5 money units. The ratio of amounts is ...

Alex : Annie = 10 : 5 = 2 : 1

Alex has 2 times as much money as Annie.

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3 years ago

The graph shows the solution to a system of inequalities:

tangare [24]

Answer:

Option A. $4x+3y\leq 12$ and $x\geq 0$

Step-by-step explanation:

we know that

The solution of the first inequality is the shaded area below the solid line $4x+3y=12$

The solid line passes through the points (0,4) and (3,0) (the y and x intercepts)

therefore

The first inequality is

$4x+3y\leq 12$

The solution of the second inequality is the shaded area to the right of the solid line x=0

therefore

The second inequality is

$x\geq 0$

7 0

3 years ago

Please help me Algebra 1

Oduvanchick [21]

Answer:

a. $\sqrt{x^n}$ = $x^\frac{n}{2}$

b. $\sqrt{x^n} = x^\frac{(n-1)}{2}\sqrt{x}$

Step-by-step explanation:

a) When <em>n </em>is even, then it is divisible by 2. Because of this, you can write:

$\sqrt{x^n} = (x^n)^\frac{1}{2}$

$\sqrt{x^n} = x^\frac{n}{2}$

b) When <em>n </em>is odd, then <em>n - 1 </em> is even. This would make it divisible by 2, and there would be a remainder of 1, so we can write:

$\sqrt{x^n} = (x^n^-^1^+^1) ^\frac{1}{2}$

$\sqrt{x^n} = (x^n^-^1$ × $x)^\frac{1}{2}$

$\sqrt{x^n} = x^\frac{(n-1)}{2}$ × $x^\frac{1}{2}$

$\sqrt{x^n} = x^\frac{(n-1)}{2}\sqrt{x}$

8 0

3 years ago

Read 2 more answers