Answer: Option D
Step-by-step explanation:
By definition if we have a function F (x) and perform a transformation of the form

Then it is true that:
If c is negative the graph of G(x) will be equal to the graph of F(x) displaced horizontally c units to the right
If c is positive, the graph of G(x) will be equal to the graph of F(x) displaced horizontally c units to the left.
Note that in this case the transformation is:

Then
and 
Therefore the graph of G(x) will be equal to the graph of F(x) displaced horizontally <em>9 units to the left</em>
The answer is the option D.
g(a)=33a−2; Find g(1)
g(1) means the value of a is 1. Replace a in the equation with 1 and solve.
33(1) - 2 = 33-2 = 31
g(1) = 31
Perentheses, probably do multiplication.
y -
y1 = m (x - x1)
where m is the slope and (x1 , y1) is the point given
m = (y2-y1)\(x2-x1)
we have <span>(-5,-3) and (6,1)
so: m = (1- -3) / (6- -5) = (1+3)/(6+5) = 4/11
and the equation of the line is:
</span>y -
y1 = m (x - x1)
y-1 = 4/11 (x-6)
simplify:
y = 4/11 x - 24/11 +1

I hope that
helps!