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3 years ago

PLEASEEE i REALLY need help!! This is due tonight!!

Mathematics

1 answer:

EleoNora [17]3 years ago

8 0

Problem 1

Two things you could measure is a person's height and the speed needed to reach the planet Mars. The person's height can be measured with a low level of precision, which means we don't need to be that accurate. We could say "that person is about 6 feet tall" and whoever is listening would get a sense of their height. In contrast, we need high precision for a rocket speed to Mars because getting this figure wrong would likely cause disaster down the road. Very complicated mathematics is essential to make sure we hit the target required in space.

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Problem 2

As mentioned, we need high precision when it comes to anything dealing with space travel. If the calculations are wrong, then the spacecraft could crash somehow. As one example where things went wrong, engineers used the wrong values and the Mars lander ended up crashing into the planet rather than landing safely. The high cost of such space exploration missions means that it's very crucial to get precise values as much as possible, to as accurate as possible. Things like discussing a person's height isn't that essential to be very precise as we can just relay estimates to whoever we're talking to. This informal setting doesn't demand as much accuracy compared to something like a rocket launch.

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Ten times an integer is added to seven times it’s square. If the result is 152, what was the original number?

Bess [88]

Answer:

Required number is 4.

Step-by-step explanation:

Let the required number be a.

Given,

Sum of ten times the integer and seven times it’s square is 152.

= > Ten times of a + seven times of it's square = 152

= > 10( a ) + 7( a )^2 = 152

= > 10a + 7a^2 - 152 = 0

= > 7a^2 + 10a - 152 = 0

= > 7a^2 + ( 38 - 28 )a - 152 = 0

= > 7a^2 + 38a - 28a - 152 = 0

= > a( 7a + 38 ) - 4( 7a + 38 ) = 0

= > ( a - 4 )( 7a + 38 ) = 0

= > a = 4 or - 38 / 7

Hence the required number is 4.

3 0

2 years ago

Andrea enjoys running. She keeps a daily journal to record how far she runs. She wears a pedometer to calculate the exact distan

Neko [114]

Answer:

14.225 kilometers.

Step-by-step explanation:

Monday 3.6

Tuesday 4.705

Wednesday 5.92

By using the addition operation, the total distance, in kilometers, that Andrea ran over the three days will be :

3.6 +4.705 +5.92=14.225

Hence, the total distance that Andrea ran over the three days = 14.225 kilometers.

5 0

2 years ago

Which of the following is true of the data represented by the box plot

zmey [24]

Answer:

The data is skewed to the bottom and contains an outlier.

Step-by-step explanation:

1. Test for outlier

An outlier is a point that is more than 1.5IQR below Q1 or above Q3.

IQR = Q3 - Q1 = 74 - 51 = 23

1.5 IQR = 1.5 × 23 = 34.5

51 - 15 = 36 > 1.5IQR

The point at 15 is an outlier.

2. Test for normal distribution

The median is not in the middle of the box.

Rather, it cuts the box into two unequal parts, so the data does not have a normal distribution.

3. Test for skewness

The longer part is to the left of the median, so the data is skewed left.

4 0

2 years ago

A 140 kg camera is suspended by two wires over a 40 metre wide football field to get shots of the action from above. At one poin

Katen [24]

Answer:

Please red the answer below

Step-by-step explanation:

In order to determine the length of each cable you use the Newton second law for each component of the forces involved in the situation.

For the x component you have:

$T_1cos\theta_1-T_2cos\theta_2=0$ (1)

T1: tension of the first cable = 1500N

T2: tension of the second cable = 800N

θ1: angle between the horizontal and the first cable

θ2: angle between the horizontal and the first cable

For the y component you have:

$T_1sin\theta_1+T_2sin\theta_2-W=0$ (2)

W: weight of the camera = Mg = (140kg)(9.8m/s^2) = 1372N

You can squared both equations (1) and (2) and the sum the two equations:

$T_1^2cos^2\theta_1=T_2^2cos^2\theta_2\\\\T_1^2sin^2\theta_1=T_2^2sin^2\theta_2-2WT_2sin\theta_2+W^2$

Then, you sum the equations:

$T_1^2(cos^2\theta_1+sin^2\theta_1)=T_2^2(sin^2\theta_2+cos^2\theta_2)-2Wsin\theta_2+W^2$ (3)

Next, you use the following identity:

$sin^2\theta+cos^2\theta=1$

and you obtain in the equation (3):

$T_1^2=T_2^2-2WT_2sin\theta_2+W^2\\\\sin\theta_2=\frac{T_2^2-T_1^2+W^2}{2WT_2}=\frac{(800N)^2-(1500)^2+(1372N)^2}{2(800N)(1372N)}=0.066\\\\\theta_2=sin^{-1}0.066=27.23\°$

With this values you can calculate the value of the another angle, by using the equation (1):

$\theta_1=cos^{-1}(\frac{T_2cos(27.23\°)}{T_1})=cos^{-1}(\frac{(800N)(cos27.23\°)}{1500N})\\\\\theta_1=61.69\°$

Now, you can calculate the length of each cable by using the information about the width of the football field. You use the following trigonometric relation:

$l_1cos\theta_1=40-d\\\\l_2cos\theta_2=d\\\\$