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expeople1 [14]
3 years ago
11

PLEASEEE i REALLY need help!! This is due tonight!!

Mathematics
1 answer:
EleoNora [17]3 years ago
8 0

Problem 1

Two things you could measure is a person's height and the speed needed to reach the planet Mars. The person's height can be measured with a low level of precision, which means we don't need to be that accurate. We could say "that person is about 6 feet tall" and whoever is listening would get a sense of their height. In contrast, we need high precision for a rocket speed to Mars because getting this figure wrong would likely cause disaster down the road. Very complicated mathematics is essential to make sure we hit the target required in space.

===============================================

Problem 2

As mentioned, we need high precision when it comes to anything dealing with space travel. If the calculations are wrong, then the spacecraft could crash somehow. As one example where things went wrong, engineers used the wrong values and the Mars lander ended up crashing into the planet rather than landing safely. The high cost of such space exploration missions means that it's very crucial to get precise values as much as possible, to as accurate as possible. Things like discussing a person's height isn't that essential to be very precise as we can just relay estimates to whoever we're talking to. This informal setting doesn't demand as much accuracy compared to something like a rocket launch.

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Help with #15 please
jonny [76]

Answer:

3 gallons of carpet shampoo

Step-by-step explanation:

room area: 16 * 15 = 240 ft

1 gallon carpet shampoo: 80 ft

240/80 = 3

3 gallons of carpet shampoo are needed.

6 0
3 years ago
Please help it's urgent.
arlik [135]

Answer:

It is the second triangle.

Step-by-step explanation:

This is because the area of the square is given as 25^2 as the perpendicular, 144^2 as the base, and the hypotenuse is 169^2.

Length of the perpendicular = 5^2 (Because 25^2 / 5^2)

Length of the base = 12^2

Length of the hypotenuse = 13^2

So, the Pythagoras theorem is,

=> H^{2} = P^{2} + B^{2}

=> 13^{2} =12^{2} +5^{2}

This is true, because, 13*13 = 12*12 + 5*5

=> 169 = 144 + 25

=> 169 = 169

If my answer helped, kindly mark me as the brainliest!!

Thanks!!

3 0
3 years ago
I don’t understand need help
RideAnS [48]

Answer: Choice D

(a-e)/f

=======================================

Explanation:

Points D and B are at locations (e,f) and (a,0) respectively.

Find the slope of line DB to get

m = (y2-y1)/(x2-x1)

m = (0-f)/(a-e)

m = -f/(a-e)

This is the slope of line DB. We want the perpendicular slope to this line. So we'll flip the fraction to get -(a-e)/f and then flip the sign from negative to positive. That leads to the final answer (a-e)/f.

Another example would be an original slope of -2/5 has a perpendicular slope of 5/2. Notice how the two slopes -2/5 and 5/2 multiply to -1. This is true of any pair of perpendicular lines where neither line is vertical.

8 0
3 years ago
Can you give me a word problem that can be solved by finding the difference of 432,906 and 61,827.
notka56 [123]
Laurence bought 432,906 lbs of soil for her garden. She only used 61,827 lbs. How much lbs of soil does she have left over?

7 0
3 years ago
Read 2 more answers
FIRST TO ANSWER GETS BRAINLIEST!
scZoUnD [109]

Answer:

\huge \boxed{ \red{ \boxed{c)78 \: units ^{2} }}}

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
  • circle
  • PEMDAS
<h3>tips and formulas:</h3>
  • \rm \:A_{shaded}=  \dfrac{\theta}{360}  \times \pi {r}^{2}
<h3>let's solve:</h3>
  1. \sf sustitute \: the \: value \: of \:  \theta \: and \: r :  \\ A_{shaded} =  \frac{140}{360}  \times \pi \times  {8}^{2}
  2. \sf simpify \: squre :  \\ A_{shaded} =  \frac{140}{360}  \times \pi \times  64
  3. \sf simpify \: fraction:  \\ A_{shaded} =  \frac{7}{18}  \times \pi \times  64
  4. \sf  reduce \: 64:  \\ A_{shaded} =  \frac{7}{ \cancel{ \: 18} \:  ^{9} }  \times \pi \times  \cancel{ 64}  \: ^{32}  \\ A_{shaded} =  \frac{7}{9} \times \pi \times 32\\ A_{shaded} =  \frac{224\pi}{9}

\large A_{shaded}\approx 78 \: square  \: units

8 0
2 years ago
Read 2 more answers
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