Tahmid has 96 figures, Sandeep has 1/3 of it so
96(1/3) = 96/3 = 32
Sandeep has 32 figures
Tahmid 96 ; Sandeep 32
How many must tahmid give so they have the same figures?
First take the difference of the two so we know how many tahmid can give.
96-32 = 64
now they each have 32 and 64 give or keep. for each one tahmid gives, he must keep one himself so to match the number they both own. so we divide the number of 2, one part to give, the other part to keep himself.
64/2 = 32
So, Tahmid must give Sandeep 32 figures to have equal number of figures of 64 each.
The answer is 8 and 13
<span>
y = ax + b
y = 4, x = 1 </span>⇒ 4 = a + b
y = 6, x = 3 ⇒ 6 = 3a + b
Solve the system of equation:
a + b = 4
3a + b = 6
______
b = 4 - a
3a + b = 6
______
3a + 4 - a = 6
2a + 4 = 6
2a = 6 - 4
2a = 2
a = 2/2 = 1
b = 4 - a = 4 - 1 = 3
So, the function rule is: y = x + 3
Thus, if x = 7, then y = 7 + 3 = 10
If x = 10, then y = 10 + 3 = 13
x y
1 4
3 6
4 7
5 8
7 10
10 13
1.8288 de diâmetro
1pés e equivalente a 0.3048 e so multiplicar por 6 que vai da 1.8288
