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2 years ago

4 times as much as the sum of 1/5 and 2/3

Mathematics

2 answers:

Softa [21]2 years ago

4 0

Answer:

3 7/15

Step-by-step explanation:

Hi,

4 (1/5 +2/3)

Find common denominators...

1/5 = 3/15

2/3 = 10/15

Add...

13/15

Now, multiply...

4 (13/15)

52/15

Simplify...

3 7/15

Hope this helped :)

madreJ [45]2 years ago

3 0

3 7/15 dndnsnsnssbsbsbsbsbsb

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Answer:

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3 years ago

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kipiarov [429]

Answer:

Graph C

Step-by-step explanation:

First, we need to find the bottom of the parabola (or the top, left, or right). In this case, it is x=3, therefore meaning y=-25. The only one that has (3,-25), so Graph C.

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2 years ago

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Increase 140 bye 10%

Rus_ich [418]

10% of 140 is 14 so just add 14 to 140

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2 years ago

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5. Mrs.Weed's puppy weighed o.236 kg when it was born. At the next check-up it weighed 0.37 kg. How much weight had it gained?

musickatia [10]

Answer:

5.) 0.134 kg.

6.) 6.15 km.

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2 years ago

Medical scientists study the effect of acute infection on tissue-specific immunity. In a collection of experiments under the sam

Serjik [45]

Answer:

The 95% confidence interval for the true proportion of mice that will test positive under similar conditions is (0.5291, 0.6429).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence interval $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

Z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

In a collection of experiments under the same conditions, 44 of 75 mice test positive for lymphadenopathy. This means that $n = 75$ and $\pi = \frac{44}{75} = 0.586$ .

Compute a 95% confidence interval for the true proportion of mice that will test positive under similar conditions.

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.586 - 1.96\sqrt{\frac{0.586*0.414}{75}} = 0.5291$

The upper limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.586 + 1.96\sqrt{\frac{0.586*0.414}{75}} = 0.6429$

The 95% confidence interval for the true proportion of mice that will test positive under similar conditions is (0.5291, 0.6429).

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2 years ago