A fair number cube, numbered from 1 to 6, is rolled. What is the probability that the number is some number other than 6?
2 answers:
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Answer:
A) But if anyone thinks this they should go back to preschool
Step-by-step explanation:
On any other value of x you would take the numerators and denominators and multiply them across:
But, this literally does not make since considering the fact that you cannot divide any value by zero. Try it, it won't work. If we plug these into a trusty dusty calculator, we get this:
0*DOMAINERROR= You can't do it.
There are other reasons why you can't divide by zero, I would suggest looking them up on YT and learning about them.
I would answer A, but the person who wrote this question just wasn't focusing when they wrote the question.