<em>Jason violated the </em><em>confidentiality of information.
</em>
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<em>Part of information security is "confidentiality of information" wherein an employee must kept all the information he may acquire when he is working in a company, confidential. When we say confidential, he is not allowed to disclose anything that he may know about company's operation, sensitive information to anybody who is outside the company (like in the example, another organization). Because data that he might disclose may get on hands by company's competitors and it can be used against the company. They might steal ideas and strategies. </em>
Answer:
3) 44 10 44
Explanation:
Given data
int [] val = { 3, 10, 44 };
The total number of parameters of given array are 3, so total length of array is also 3.
The indexing of array starts with '0', Therefore the <u>indexes</u> of array with length zero are: {0,1,2}
The value of array at index 0 is = 3
similarly
value at index 1 = 10
value at index 2 = 44
Any value of index 'i' of an array is selected using array[i].
Therefore,
val[0] is selecting the value of array located at index '0'.
val[0] = 3
val[2] is selecting the value of array located at index '2'.
val[2] = 44
Finally,
val[0] = val[2]; is copying the value placed at index 2 (44) to value placed at index 0 (3). Hence, the output would be { 44 10 44}. So 3rd option is correct.
Answer:
See Explaination
Explanation:
package testscores;
import java.util.ArrayList;
import java.util.List;
public class TestScores {
public List<Integer> scorearray=new ArrayList<>();
public TestScores(List<Integer> scores) throws InvalidTestScore{
this.scorearray=scores;
for(int i=0;i<scorearray.size();i++){
if(scorearray.get(i)>100 || scorearray.get(i)<0){
throw new InvalidTestScore(this.scorearray.get(i));
}
}
}
public double average(){
int tot=0;
for(int i=0;i<this.scorearray.size();i++){
tot=tot+this.scorearray.get(i);
}
return tot*(1.0)/(this.scorearray.size());
}
class InvalidTestScore extends Exception
{
private double amount;
public InvalidTestScore(int Score)
{
System.out.println("Invalid Score "+Score);
}
}
}
public class MyClass {
public static void printChar(char ch1, char ch2, int numberPerLine){
int i = 0;
for (char c = ch1; c <= ch2; c++){
while (i < numberPerLine){
System.out.print(c + " ");
i += 1;
}
System.out.println("");
i = 0;
}
}
public static void main(String args[]) {
printChar('a', 'z', 10);
}
}
So far, this works by printing letters. If you need me to modify the code, I will.
Back then, movies were black and white because they had cameras that could only see black and white. In the late 1900's and early 2000's, they developed color cameras. But the common resolution and screen size was 640x480 or 4:3. Nowadays, in the late 2000's and early 2010, the widescreen format was more commonly used for many reasons. Today, the common colors are RGB 1M colors, and the resolution is 16:9. Some movies like to go even farther, like me, and use 21:9,which is super widescreen. That is more immersive than 16:9, and gives the watcher a wider, better experience.
