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murzikaleks [220]
3 years ago
12

Please help I’m stuck

Mathematics
2 answers:
solong [7]3 years ago
8 0

Answer:

23

hope it helps u :)

Step-by-step explanation:

2x+13

x=5

=2×5+13

=10+13

=23

anyanavicka [17]3 years ago
6 0

Answer:

23

Step-by-step explanation:

When I was first introduced to algebra, One thing that had me stumped for the longest time is terms like "2x".  This is because nobody explained to me that saying "2x" and similar terms implies a multiplication.  so "2x" actually means "2 × x".  I only mention this because I thought maybe it would help.

To solve it then, all we need to do then is think of "x" as meaning five, and it being multiplied by 2

We're given this:

2x + 13

which you can also read as this:

2 \times x + 13

We're told x equals five, so we can say:

2 \times 5 + 13

Remember when solving this, that multiplication and division <em>always</em> come before addition and subtraction, so let's do the multiplication:

10 + 13

and then add it up:

23

So the final answer is twenty-three.

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Answer:

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murzikaleks [220]

Answer:

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Step-by-step explanation:

Remember the Order of Operations:

Parentheses

Exponents

Multiplication

Division

Addition

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*But always solve from left to right so there can be times where you either have to do division before multiplication or subtraction before addition

1. 14 + <u>18 ÷ 2 </u>x 18 – 7

14+<u>9 x 18</u>-7

<u>14+162</u>-7

176-7

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2. <u>15 x 10</u> + 12 ÷ 3 + 9

150+<u>12÷3</u>+9

<u>150+4</u>+9

154+9

163

3. <u>8 x 4</u> + 9 – 9 + 18

<u>36+9</u>-9+18

<u>45-9</u>+18

36+18

54

4. 2 - 1 +<u> 5 x 4 </u>x 11

2-1+<u>20x1</u>1

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60-<u>9x6</u>

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6

6. <u>(10 ÷ 5)</u>3 + 100 – 9 x 11

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106-99

7

7. <u>3 x 8</u> x 2 – 42 + 5

<u>24x2</u>-42+5

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6+5

11

8. <u>14 ÷ 2</u> -1 + 3

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9

6 0
3 years ago
Of the numbers 8, 9, 10, 11, and 12, which are solutions to the inequality 8p&lt;84?
Allushta [10]
<span>8p<84
p<84/8
p<10.5

answer
</span><span>8, 9, 10 are solutions</span>
7 0
3 years ago
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ella [17]

Answer:

1. The red one

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Step-by-step explanation:

I use the way to calculate the percentage in question 2 and 3

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