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omeli [17]
3 years ago
10

Suppose JM= 5x-10 and MK= x+14 and M is the midpoint of JK. Find x and JM

Mathematics
1 answer:
liubo4ka [24]3 years ago
3 0
Because M is the midpoint of segment JK, JM=MK.

Now, substitute, and you will get 5x-10=x+14.
You can easily solve from here.


5x-10=x+14
5x-x-10=x-x+14
4x-10=14
4x-10+10=14+10
4x=24
4x/4=24/4
x=6

Since we now know x=6 and the two segments are congruent, both JM and MK are 6.

JM+MK= 6+6=12, therefore JK=12.
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4 0
2 years ago
The tickets for a dance recital cost $5.00 for adults and $2.00 for children. If the total number of tickets sold was 295 and th
dem82 [27]
To solve, you would need to make two equations and substitute one in for the other. Let a = # of adults, and c = # of children

5a + 2c = 1,220
a + c = 295

a + c = 295
-c         -c
a = 295 - c

5(295 - c) + 2c = 1,220
1,475 - 5c + 2c = 1,220
1,475 - 3c = 1,220

1,475 - 3c = 1,220
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-3c/-3 = -255/-3
c = 85

a + c = 295
a + 85 = 295
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a = 210

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Hope this helps!
6 0
3 years ago
Kyle drives 330 miles on 15 gallons of gas. How many miles per gallon (mpg) did Kyle get? A) 12 mpg B) 16 mpg C) 19 mpg D) 22 mp
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5 0
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Simplify the problem
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Answer:

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(The rule is add 3)

3 0
3 years ago
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