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vivado [14]
4 years ago
13

Cesar is creating a schedule to practice his instrument for band. He needs to practice for a total of 10 hours in a week. On Mon

day he practice for 1 12 1 2 12 1 2 hours, on Tuesday he practiced for 2 14 1 4 14 1 4 hours, and on Wednesday he practiced for 1 12 1 2 12 1 2 hours. How many hours does Cesar need to practice during the rest of the week in order to have his 10 total hours?
Mathematics
1 answer:
ratelena [41]4 years ago
5 0

Answer: See explanation

Step-by-step explanation:

Your question isn't really clear. Let me help you rephrase it and solve.

Let's say Cesar is creating a schedule to practice his instrument for band. He needs to practice for a total of 10 hours in a week. On Monday he practice for 1 1/2 hours, on Tuesday he practiced for 2 1/4 hours, and on Wednesday he practiced for 1 1/2 hours.

The total hours that Cesar has used in practicing will be:

= 1 1/2 + 2 1/4 + 1 1/2

= 5 1/4

To get the number of hours that Cesar need to practice during the rest of the week in order to have his 10 total hours, we subtract 5 1/4 hours from 10 hours. This will be:

= 10 - 5 1/4

= 4 3/4 hours.

Cesar needs to practice for 4 3/4 hours more.

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There will be 128 organisms after 30 minutes.

Step-by-step explanation:

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The Lagrangian is

L(x,y,\lambda)=x+4y+\lambda(x^2+y^2-9)

with critical points where the partial derivatives vanish.

L_x=1+2\lambda x=0\implies x=-\dfrac1{2\lambda}

L_y=4+2\lambda y=0\implies y=-\dfrac2\lambda

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Substitute x,y into the last equation and solve for \lambda:

\left(-\dfrac1{2\lambda}\right)^2+\left(-\dfrac2\lambda\right)^2=9\implies\lambda=\pm\dfrac{\sqrt{17}}6

Then we get two critical points,

(x,y)=\left(-\dfrac3{\sqrt{17}},-\dfrac{12}{\sqrt{17}}\right)\text{ and }(x,y)=\left(\dfrac3{\sqrt{17}},\dfrac{12}{\sqrt{17}}\right)

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Which finds the solution to the equation represented by the model below?
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A

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<h3>Opening up parenthesis</h3>

The given numbers can be simplified by opening up the parenthesis as indicated above in which case,

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Original Price = $ 120, %Markup = 4%<br><br> So what’s the price?
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