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vivado [14]
3 years ago
13

Cesar is creating a schedule to practice his instrument for band. He needs to practice for a total of 10 hours in a week. On Mon

day he practice for 1 12 1 2 12 1 2 hours, on Tuesday he practiced for 2 14 1 4 14 1 4 hours, and on Wednesday he practiced for 1 12 1 2 12 1 2 hours. How many hours does Cesar need to practice during the rest of the week in order to have his 10 total hours?
Mathematics
1 answer:
ratelena [41]3 years ago
5 0

Answer: See explanation

Step-by-step explanation:

Your question isn't really clear. Let me help you rephrase it and solve.

Let's say Cesar is creating a schedule to practice his instrument for band. He needs to practice for a total of 10 hours in a week. On Monday he practice for 1 1/2 hours, on Tuesday he practiced for 2 1/4 hours, and on Wednesday he practiced for 1 1/2 hours.

The total hours that Cesar has used in practicing will be:

= 1 1/2 + 2 1/4 + 1 1/2

= 5 1/4

To get the number of hours that Cesar need to practice during the rest of the week in order to have his 10 total hours, we subtract 5 1/4 hours from 10 hours. This will be:

= 10 - 5 1/4

= 4 3/4 hours.

Cesar needs to practice for 4 3/4 hours more.

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Step-by-step explanation:

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3 years ago
a. Suppose we had $15,192 cash and invested it in the bank at 16 percent interest, how much would you have at the end of 1, 2, 3
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Answer:

Part a) \$17,622.72

Part b) \$20,442.36

Part c) \$23,713.13

Part d) \$27,507.23

Step-by-step explanation:

we know that  

The compound interest formula is equal to

A=P(1+\frac{r}{n})^{nt}

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest  in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

Part a) How much would you have at the end of 1 year?

in this problem we have

t=1\ years\\ P=\$15,192\\ r=0.16\\n=1

substitute in the formula above

A=15,192(1+\frac{0.16}{1})^{1*1}=\$17,622.72

Part b) How much would you have at the end of 2 year?

in this problem we have

t=2\ years\\ P=\$15,192\\ r=0.16\\n=1

substitute in the formula above

A=15,192(1+\frac{0.16}{1})^{1*2}=\$20,442.36

Part c) How much would you have at the end of 3 year?

in this problem we have

t=3\ years\\ P=\$15,192\\ r=0.16\\n=1

substitute in the formula above

A=15,192(1+\frac{0.16}{1})^{1*3}=\$23,713.13

Part d) How much would you have at the end of 4 year?

in this problem we have

t=4\ years\\ P=\$15,192\\ r=0.16\\n=1

substitute in the formula above

A=15,192(1+\frac{0.16}{1})^{1*4}=\$27,507.23

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