Sorry for the hand writing. But you want to factor out a 4y^2 which will result in (9y^2-1). Then you will factor out the equation in parentheses to (3y-1)(3y+1). Don’t forget to put the 4y^2 out front!
Answer:
-130.8
Step-by-step explanation:
The average of the two slope values is ...
(-148.8 -112.8)/2 = -261.6/2 = -130.8
The slope of the tangent line at t=15 is approximately -130.8.
Answer: y = 4x-3
slope = 4, y intercept = -3
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m = 4 is the slope
is the point the line goes through
Using point slope form, we can say,
The equation is in slope intercept form y = mx+b
m = 4 = slope
b = -3 = y intercept
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As an alternative, you can use y = mx+b to get the same answer. We'll plug in m = 4 and (x,y) = (-2,-11) to solve for b
y = mx+b
-11 = 4(-2)+b
-11 = -8+b
-11+8 = -8+b+8
-3 = b
b = -3 we get the same y intercept value as above
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To check the answer, plug x = -2 into the equation. We should get y = -11
y = 4x-3
y = 4(-2)-3
y = -8-3
y = -11 we get the proper y value. The answer is confirmed.