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grandymaker [24]
3 years ago
5

Find a point 1/5 of the way between points A (-6,-4) and B (-1,6).

Mathematics
2 answers:
user100 [1]3 years ago
7 0

9514 1404 393

Answer:

  (-5, -2)

Step-by-step explanation:

That point P can be found from ...

  P = A + 1/5(B -A)

  P = (4/5)A +(1/5)B = (4A +B)/5

  P = (4(-6, -4) +(-1, 6))/5 = (-24-1, -16+6)/5 = (-25, -10)/5

  P = (-5, -2)

IrinaK [193]3 years ago
6 0

Answer:

the answer is (-5,-2)

Step-by-step explanation:

:))

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(a) Suppose one house from the city will be selected at random. Use the histogram to estimate the probability that the selected
Mila [183]

Answer:

a)   0.71

b)   0.9863

Step-by-step explanation:

a. Given the mean prices of a house is $403,000 and the standard deviation is $278,000

-The probability the probability that the selected house is valued at less than $500,000 is obtained by summing the frequencies of prices below $500,000:

P(X

Hence, the probability of a house price below $500,000 is 0.71

b. -Let X be the mean price of a randomly selected house.

-Since the sample size 40 is greater than 30, we assume normal distribution.

-The probability can therefore be calculated as follows:

P(X

Thus, the probability  that the mean value of the 40 houses is less than $500,000 is 0.9863

8 0
4 years ago
MARKING AS BRAINLIEST! LAST ATTEMPT! ) show ur work
matrenka [14]

Answer:

\sqrt{28} =\sqrt{(7)(4)} =2\sqrt{7} \\\sqrt{40} =\sqrt{(10)(4)} =2\sqrt{10} \\\sqrt{108} =\sqrt{(36)(3)} =6\sqrt{3} \\\sqrt{125} =\sqrt{(25)(5)} =5\sqrt{5}

-6\sqrt{81} =-6(9)=-54

\sqrt{80} =\sqrt{(16)(5)} =4\sqrt{5)} \\3\sqrt{60} =3\sqrt{(15)(4)} =(3)(2)\sqrt{15} =6\sqrt{15}

-\sqrt{200} =-\sqrt{(100)(2)} =-10\sqrt{2}

4\sqrt{320} =4\sqrt{(64)(5)} =(4)(8)\sqrt{5} =32\sqrt{5}

Hope this helps

7 0
3 years ago
The width of a rectangle is 6 kilometers less than twice its length. if its area is 108 square​ kilometers, find the dimensions
Art [367]
Hi there!

Answer:
length = 9 kilometres
Width = 12 kilometres

Let's solve this problem step by step!
To find our answer we need to set up and solve an equation.

Let the length of the rectangle be represented by x.
The width of the rectangle can therefore be expressed by 2x - 6.

The area of a rectangle can be found by using the formula:
A = width × length

Plug in the data from the formula
A = x (2x - 6).

Simplify using rainbow technique.
x(2x - 6) = 2 {x}^{2} - 6x

Now we've found the simplified expression that expresses the area of the rectangle. Therefore, we can now set up and start solve the equation.

2 {x}^{2} - 6x = 108
Subtract 108

2 {x}^{2} - 6x - 108 = 0
Divide by 2.

{x}^{2} - 3x - 54
(x - 9)(x + 6) = 0
Rule AB = 0, gives A is 0 or B is 0.

x - 9 = 0 \\ x = 9 \\ \\ x + 6 = 0 \\ x = - 6

The length of the rectangle, which was represented by x, must be 9 (since it cannot be a negative number).

Length
x = 9
Width
2x - 6 = 2 \times 9- 6 = 18 - 6 = 12

Answer:
length = 9 kilometres
Width = 12 kilometres

~ Hope this helps you!
6 0
3 years ago
Carlos evaluated 20 - (2x6) + 8 ÷4 and got 29. Is his answer correct? If not, explain what Carlos did wrong and find the correct
natima [27]
20-(2x6) +8 divided by 4
2 times 6 = 12
8/4 = 2
20-12+2
It would be 14 not 29

He used PEMDAS in the wrong order
8 0
4 years ago
Read 2 more answers
Imagine you are trying to maximize the calories you burn in a 60-minute workout you do a few times a week. Running burns 9 calor
amm1812
Running burns the most calories folwed by aerobic

so max out the most and min the least


most running
running has no limit, so see least

aerobic, aerobic has to be at most 30 (less than 30)

rowing has to be at least 15 mins
say row=15 mins

then you have 45 mins left
max out on running (minus 1 tho to do running)

so
44mins running 1 min run, 15min row
total calories=507 calories burned

the way to do it is
x=running minutes
y=aerobic minutes
z=rowing minutes

x+y+z=60
9x+6y+7z=max calories
x≥5
y≤30
z≥15
those are the equations
not sure what the objective function is
8 0
3 years ago
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