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earnstyle [38]
3 years ago
14

Write the ratios for sin x and cos x.

Mathematics
1 answer:
alukav5142 [94]3 years ago
8 0

Answer:

Sine x = \frac{opposite}{hypothenuse}\\

Sine x = \frac{\sqrt{119} }{12}

Cosine x = \frac{adjacent}{hypothenuse}

Cosine x = \frac{5}{12}

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HELPPPPP SOMEONEEEEE
velikii [3]
QR = 23

Because the triangles are equal to each other, sides QR and TV are also equal. You can create an 3 or 4 step equation by writing the the QR equation is equal to the TV equation and then solving for X. After you solve for X, plug it back into the QR equation to solve for QR.
7 0
3 years ago
The figure is cut into 15 equal pieces. 2. Shade of the figure. 5​
oksano4ka [1.4K]

Answer:

Each equal part is called one-fourth or a quarter of the whole sheet. Thus, any whole can be divided into four equal parts and each part is one-fourth or a quarter of the whole. It is expressed as 1/4 and read as one over four or one upon four.

Step-by-step explanation:

7 0
3 years ago
Paula goes to the store and buys a binder, a folder, and a highlighter. The highlighter's cost is half the cost of the binder, a
tatyana61 [14]

Answer:

Cost of the binder = $5

Cost of the highlighter = $2.5

Cost of the folder = $2

Step-by-step explanation:

Let

Cost of the binder = x

Cost of the highlighter = 1/2x

Cost of the folder = x - 3

Total cost = $9.50

Total cost = Cost of the binder + Cost of the highlighter + Cost of the folder

9.50 = (x) + (1/2x) + (x-3)

9.50 = x + 1/2x + x - 3

9.50 + 3 = x + 1/2x + x

12.50 = 2x + 1/2x

12.50 = 2 1/2x

12.50 = 5/2x

x = 12.50 ÷ 5/2

= 12.50 × 2/5

= 25/5

x = $5

Cost of the binder = x = $5

Cost of the highlighter = 1/2x = 1/2*6 = $2.5

Cost of the folder = x - 3

= 5 - 3 = $2

3 0
3 years ago
153 of the 258 high school students surveyed at a local school said they went outside more during school hours as elementary sch
Juli2301 [7.4K]

<u>Answer-</u>

<em>It </em><em>is reasonable</em><em> that the state education department claims the percentage for the entire state is 63%.</em>

<u>Solution-</u>

153 out of the 258 high school students surveyed at a local school said they went outside more during school hours as elementary school students than they do now as high school students.

Here,

x = 153,

n = 258,

Then,

\text{sample proportion}=p=\dfrac{153}{258}=0.5930=59.30\%

And,

\text{Margin Error}=2\times \sqrt{\dfrac{p(1-p)}{n}}

Putting the values,

\text{ME}=2\times \sqrt{\dfrac{(0.5930)(1-0.5930)}{258}}\\\\=2\times \sqrt{\dfrac{(0.5930)(0.407)}{258}}\\\\=2\times \sqrt{\dfrac{0.2414}{208}}\\\\=2\times 0.0341\\\\=0.0682\\\\=6.82\%

The interval would be,

=(59.30-6.82,\ 59.30+6.82)\\\\=(52.48,\ 66.12)

As population proportion p=63% lies in this interval, so it is reasonable.

5 0
4 years ago
In a marathon,90% of runners managed to complete it and 30% where men.if 270 men completed it, how many total runners began the
creativ13 [48]
540? I’m not 100% sure though
8 0
4 years ago
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