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2 years ago

Y=5/2x−8

Mathematics

2 answers:

ElenaW [278]2 years ago

7 0

The answer will be 0,-8

Levart [38]2 years ago

3 0

One solution: (0,-8) is the answer

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What is the square root of 1675

liubo4ka [24]

40.9267 is the square root

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2 years ago

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Expand and simplify (x+3)²

Ivenika [448]

Answer:

Step-by-step explanation:

expand and simplify (x+3)²

(x+3)² =

x² + 9 + 2 × x × 3 =

x² + 9 + 6x

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2 years ago

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Find the values of x: I don’t understand how to do this please help

goblinko [34]

Answer:

x = 8

Step-by-step explanation:

11x - 34 and 7x - 2 are vertical angles and congruent, thus

11x - 34 = 7x - 2 ( subtract 7x from both sides )

4x - 34 = - 2 ( add 34 to both sides )

4x = 32 ( divide both sides by 4 )

x = 8

-----------------------

11x - 34 = 11(8) - 34 = 88 - 34 = 54

18y and 11x - 34 are adjacent angles and supplementary , thus

18y + 54 = 180 ( subtract 54 from both sides )

18y = 126 ( divide both sides by 18 )

y = 7

8 0

3 years ago

Ivan used coordinate geometry to prove that quadrilateral EFGH is a square.

Gelneren [198K]

Answer:

(A)Segment EF, segment FG, segment GH, and segment EH are congruent

Step-by-step explanation:

Step 1

Quadrilateral EFGH with points E(-2,3), F(1,6), G(4,3), H(1,0)

Step 2

Using the distance formula

$Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Given E(-2,3), F(1,6)

$|EF|=\sqrt{(6-3)^2+(1-(-2))^2}=\sqrt{3^2+3^2}=\sqrt{18}=3\sqrt{2}$

Given F(1,6), G(4,3)

$|FG|=\sqrt{(3-6)^2+(4-1)^2}=\sqrt{3^2+3^2}=\sqrt{18}=3\sqrt{2}$

Given G(4,3), H(1,0)

$|GH|=\sqrt{(0-3)^2+(1-4)^2}=\sqrt{(-3)^2+(-3)^2}=\sqrt{18}=3\sqrt{2}$

Given E (−2, 3), H (1, 0)

$|EH|=\sqrt{(0-3)^2+(1-(-2))^2}=\sqrt{(-3)^2+(3)^2}=\sqrt{18}=3\sqrt{2}$

Step 3

Segment EF ,E (−2, 3), F (1, 6)

Slope of |EF|= $\frac{6-3}{1+2} =\frac{3}{3}=1$

Segment GH, G (4, 3), H (1, 0)

Slope of |GH| $= \frac{0-3}{1-4} =\frac{-3}{-3}=1$

Step 4

Segment EH, E(−2, 3), H (1, 0)

Slope of |EH| $= \frac{0-3}{1+2} =\frac{-3}{3}=-1$

Segment FG, F (1, 6,) G (4, 3)

Slope of |EH| $=\frac{3-6}{4-1} =\frac{-3}{3}=-1$

Step 5

Segment EF and segment GH are perpendicular to segment FG.

The slope of segment EF and segment GH is 1. The slope of segment FG is −1.

Step 6

Segment EF, segment FG, segment GH, and segment EH are congruent.

The slope of segment FG and segment EH is −1. The slope of segment GH is 1.

Step 7

All sides are congruent, opposite sides are parallel, and adjacent sides are perpendicular. Quadrilateral EFGH is a square

4 0

3 years ago

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Plz answer ASAP with work ty!

horsena [70]

Answer: $8\sqrt{6}$

Step-by-step explanation:

$\frac{2^4\sqrt{3}}{\sqrt{2}}$

$2^{\frac{7}{2}}\sqrt{3}$

$2^{\frac{7}{2}}=2^{3+\frac{1}{2}}$

$2^3\cdot \:2^{\frac{1}{2}}$ =

$2^3\sqrt{2}$

= $2^3\sqrt{2}\sqrt{3}$ =

$2^3\sqrt{2\cdot \:3}$

= $2^3\sqrt{6}$

$2^3=8$

Answer- $8\sqrt{6}$

7 0

3 years ago