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vivado [14]
3 years ago
15

Please help answer and explain am begging you ​

Mathematics
2 answers:
Airida [17]3 years ago
7 0
1,6,7 are positive
2,9 are negative
3,4,5,8 are undefined
Inessa05 [86]3 years ago
4 0

Answer:

1.) positive

2.) negative

3.) zero

4.) undefined

5.) zero

6.) positive

7.) positive

8.) undefined

9.) negative

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Which is correct regarding the statement: “If x is an odd integer, then the median of x , x + 2, x + 6, and x + 10 is an odd num
mario62 [17]
X is an odd number 

x+2 is also odd (consider the example x = 3 so x+2 = 3+2 = 5). Adding 2 to any odd number is always odd

Similarly, so is x+6 (since we have x+2+2+2).  

And so is x+10 (x+2+2+2+2+2). 

So every value in this list is an odd number. The middle most values are x+2 and x+6 which are both odd.

Adding any two odd numbers together yields an even number. For example 3+5 = 8. Divide this even number in half and we may or may not get an odd number (eg: 8/2 = 4 and 6/2 = 3)

So this statement is sometimes true
8 0
4 years ago
Read 2 more answers
A rectangle with the vertices (3, -2), (3, -4), (7, -2), (7, -4) is reflected across the x-axis and the rotated 90 degrees count
irga5000 [103]

Answer:

The new vertices are: (-2,3),(-4,3),(-2,7),(-4,7)

Step-by-step explanation:

The given vertices are (3,-2),(3,-4),(7,-2),(7,-4)

Rule for reflection about x axis is (x,y)→(x,-y).

So, (3,-2)→(3,2)

     (3,-4)→(3,4)

     (7,-2)→(7,2)

     (7,-4)→(7,4)

Now, new vertices after reflection about x axis are (3,2),(3,4),(7,2),(7,4).

Rule for 90 degree rotation counter-clockwise is (x,y)→(-y,x).

So, (3,2)→(-2,3)

     (3,4)→(-4,3)

     (7,2)→(-2,7)

     (7,4)→(-4,7)

Therefore, the new rectangle after reflection about x axis and rotated 90 degrees counter-clockwise has the following vertices:

(-2,3),(-4,3),(-2,7),(-4,7)

4 0
3 years ago
Circle A has a center at the origin and a point M located on the circle at (1,0). Circle B has a center at (-2,1) and point N lo
kvasek [131]
Do you still need help on this?
5 0
3 years ago
If an injectable solution contains 25μg of a dug substance in each 0.5 mL, how many milliliters would be required to provide a p
Kay [80]

Answer:

5mL would be required to provide a patient with 0.25 mg of the drug substance.

Step-by-step explanation:

The problem states that an injectable solution contains 25μg of a dug substance in each 0.5 mL, and asks how many milliliters would be required to provide a patient with 0.25 mg of the drug substance.

So, the first step is the conversion of 25ug to mg, since the problem asks the answer in mg.

Each mg has 1000ug. So

1mg - 1000ug

xmg - 25ug

1000x = 25

x = \frac{25}{1000}

x = 0.025 mg

It means that each 0.5mL of the solution contains 0.025mg of the drug. How many milliliters would be required to provide a patient with 0.25 mg of the drug substance.

0.5mL - 0.025mg

xmL - 0.25mg

0.025x = 0.5*0.25

x = \frac{0.5*0.25}{0.025}

x = 10*0.5

x = 5mL

5mL would be required to provide a patient with 0.25 mg of the drug substance.

6 0
3 years ago
Hannah and Tim collect stamps. Tim is bringing his stamps to Hannah's house so they can compare. Hannah has 60 stamps. Which exp
Free_Kalibri [48]
<span>The expression represents the total number of stamps that they will have if t represents the number of stamps Tim </span>

Can be solve by adding the stamps of tim and Hannah

Let x be the total stamps of tim and Hannah

X = 60 + t

6 0
4 years ago
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