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Brrunno [24]
3 years ago
8

What is the opposite of love​

Mathematics
2 answers:
Nitella [24]3 years ago
6 0

Answer:

Hate is opposite of love

Solnce55 [7]3 years ago
3 0

Answer:

opposite of love is hate

hope this answer will help you

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Subtract: 2x^2 - 4x - 3 from x^2 - 5x - 8.
lesya692 [45]
The answer is: -x^2-x-5           
8 0
3 years ago
What is the result when 10 is increased by 3%
Lilit [14]

Answer:

Step-by-step explanation:

10 + 3% of 10 = 10 + (3/100) *10

                     = 10 + 3*10/100

                     = 10 + 3/10

                     = 10 + 0.3

                      =  10.3

6 0
4 years ago
Consider the expansion of (5p + 2q)^6. Determine the coefficients for the terms with the powers of p and q shown.
Step2247 [10]

Answer:

Remember, the expansion of (x+y)^n is (x+y)^n=\sum_{k=0}^n \binom{n}{k}x^{n-k}y^k, where \binom{n}{k}=\frac{n!}{(n-k)!k!}.

Then,

(5p+2q)^6=\sum_{k=0}^6\binom{6}{k}(5p)^{6-k}(2q)^k=\sum_{k=0}^6\binom{6}{k}5^{6-k}2^k p^{6-k}q^k

Then, the coefficient of the term p^{6-k}q^k is \binom{6}{k}5^{6-k}2^k

a) since 6-k=2, then k=4. So the coefficient of p^2q^4 is

\binom{6}{4}5^{6-4}2^4=15*5^2*2^4=15*25*16=6000

b) since 6-k=5, then k=1. So, the coefficient of p^5q is

\binom{6}{1}5^{6-1}2^1=6*5^5*2=37500

c) since 6-k=3, then k=3. So, the coefficient of p^3q^3 is

\binom{6}{3}5^{6-3}2^3=20*5^3*8=20000

6 0
3 years ago
Lines m and n are perpendicular if the slope of m is zero then the slope of n is
Tpy6a [65]

Answer:

undefined

Step-by-step explanation:

A line with a slope of zero is a horizontal line parallel to the x- axis

Thus, a line perpendicular to it is a vertical line parallel to the y- axis, with an undefined slope.

5 0
3 years ago
Apply the distributive property to create an equivalent expression 1/3(3j+6) what the answer
Anna71 [15]

Answer:

\large\boxed{\dfrac{1}{3}(3j+6)=j+2}

Step-by-step explanation:

The distributive property: <em>a(b + c) = ab + ac</em>.

\dfrac{1}{3}(3j+6)=\left(\dfrac{1}{3\!\!\!\!\diagup_1}\right)(3\!\!\!\!\diagup^1j)+\left(\dfrac{1}{3\!\!\!\!\diagup_1}\right)(6\!\!\!\!\diagup^2)=1j+(1)(2)=j+2

6 0
3 years ago
Read 2 more answers
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