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3 years ago

I’ve been stuck on this for a few minutes. I’m not really sure what to do..

Mathematics

1 answer:

rewona [7]3 years ago

7 0

Answer:

Step-by-step explanation:

You know that the three angles of a triangle add up to 180°. If one angle is 38° and another angle is 67°, then the third angle must be 180°-38°-67° = 75°.

You have a straight line across the bottom, and three angles meeting in the middle of it. Those three angles add up to 180°. One of them is 75°, another is 50°, so the third angle must be 180°-75°-50° = 55°.

That leaves you with one unknown angle. ? = 180°-40°-55° = 85°

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How do you the equation of the line that passes through point (-3,2) and is parallel to the line formed by the equation y = 4x +

hjlf

Answer:

y = 4x + 14

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 4x + 7 ← is in slope- intercept form

with slope m = 4

• Parallel lines have equal slopes , then

y = 4x + c ← is the partial equation

to find c substitute (- 3, 2 ) into the partial equation

2 = - 12 + c ⇒ c = 2 + 12 = 14

y = 4x + 14 ← equation of parallel line

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2 years ago

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Step-by-step explanation:

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2 years ago

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1. What is the solution of n² – 49 = 0? (1 point)

maks197457 [2]

Answer:

1. $n=\pm7$

2. $x=\pm7i[tex]3.[tex]\pm 12x =a$

4. 22

Step-by-step explanation:

1. $n^2 - 49 = 0$

$n^2 =49$

$n= \sqrt{49}$

$n=\pm7$

2. $x^2+64 = 0$

$x^2 =-64$

$x= \sqrt{49}$

$x=\pm7i[tex]3. Area of square = [tex]a^{2}$

Where a is the side

We are given an area o square = $144x^{2}$

So, $144x^{2}=a^{2}$

$\sqrt{144x^{2}}=a$

$\pm 12x =a$

4. We are given that the solution of quadratic equation -9 and 9

So, equation becomes:

$(x+9)(x-9)=0$

$x^2- 81=0$

So, in the given equation $x^2 + z = 103$

z should be the number from which if we subtract 103 so we get 81

Substitute z = 22

$x^2 + 22 = 103$

$x^2 + 22 -103=0$

$x^2 -81=0$

Thus the value of z is 22

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