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2 years ago

7d-12+2d+3=18 solve variable. include steps, also check your answer!

Mathematics

1 answer:

Zinaida [17]2 years ago

8 0

this is the answer

i have checked this answer thrice

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In January. The temperature in Fargo, North Dakota is -2 F. On the same day, the temperature in Cheyenne, Wyoming was 1 F. Write

zaharov [31]

Answer:

(a) $1 > -2$ or $-2 < 1$

(b) $2 > 1$ or $1 < 2$

Step-by-step explanation:

Given

$N = -2F$ --- North Dakota

$C = 1F$ --- Cheyenne, Wyoming

Solving (a): Inequality to compare both temperatures

From the given temperatures, we can conclude that:

$C > N$ or $N < C$

Because

$1 > -2$ i.e. 1 is greater than -2

$-2 < 1$ i.e. -2 is less than 1

Solving (b): Inequality to compare the absolute values of the temperatures

We have:

$N = -2F$

$C = 1F$

The absolute values are:

$|N| = |-2|$

$|N| =2$

$|C| = |1|$

$|C| = 1$

By comparison:

$|N| > |C|$ or $|C| < |N|$

Because

$2 > 1$ i.e. 2 is greater than 1

$1 < 2$ i.e. 1 is less than 2

4 0

2 years ago

Evaluate the determinant of the matrix.<br> -4 5 6<br> 0 4 4<br> -2 -5 4<br> I need the work plz

FromTheMoon [43]

Answer:

-136

Step-by-step explanation:

We have to find the determinant of the following matrix:

$\left[\begin{array}{ccc}-4&5&6\\0&4&4\\-2&-5&4\end{array}\right]$

We can find the determinant by expanding via 1st column. i.e. by taking each element of 1st column and multiplying it by its co-factor matrix as shown below:

det $\left[\begin{array}{ccc}-4&5&6\\0&4&4\\-2&-5&4\end{array}\right]$

= $(-4 \times det \left[\begin{array}{cc}4&4\\-5&4\end{array}\right]) - (0 \times (-4 \times det \left[\begin{array}{cc}5&6\\-5&4\end{array}\right]))+ ((-2) \times det\left[\begin{array}{cc}5&6\\4&4\end{array}\right])\\\\ =-4 \times (16 + 20)-(0)+(-2 \times 20-24)\\\\ =-4(36)+(-2(-4))\\\\ =-144+8\\\\ =-136$