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Anna11 [10]
3 years ago
14

Find the area of the shaded region. (please!!!)

Mathematics
1 answer:
Mashutka [201]3 years ago
6 0

Answer:

12.5 m²

Step-by-step explanation:

The shaded area is a triangle whose area (A) can be calculated as

A = \frac{1}{2} bh ( b is the base and h the perpendicular height )

Here b = 8 - 3 = 5 and h = 5 , then

A = \frac{1}2} × 5 × 5 = 0.5 × 25 = 12.5 m²

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Will the following list have a large or small Standard Deviation?
jek_recluse [69]

Answer:

large

Step-by-step explanation:

3 0
3 years ago
PLEASE HELP!!!!
Lisa [10]

Answer:

x = - 3 with multiplicity 2

Step-by-step explanation:

f(x) = (x - 3)(x + 3)(x + 3) = (x - 3)(x + 3)²

Equating each factor to zero and solving for x

x - 3 = 0 ⇒ x = 3 with multiplicity 1

x + 3 = 0 ⇒ x = - 3

x + 3 = 0 ⇒ x = -3

Thus x = - 3 has multiplicity of 2

The fact that the factor is squared gives the multiplicity

(x + 3)³ has root - 3 of multiplicity 3

8 0
3 years ago
Under the translation T(2, -3) the point (1, 6) will become (3, 9).
seraphim [82]

Answer:

False (under assumption T(2,-3) means move it right 2 units and down 3 units).

Step-by-step explanation:

The statement is false.

T(2,-3) means move the point right 2 (so plus 2 on the x-coordinate) and down 3 units (so minus 3 on the y-coordinate).

So (1,6) will become (1+2,6-3)=(3,3) after the translation.

The point (1,12) will become (1+2,12-3)=(3,9).

If the statement were "Under the translation T(2,-3) the point (1,12) will become (3,9)", then it would be true.

Or!

If the statement were "Under the translation T(2,3) the point (1,6) will become (3,9)", then it would be true.

3 0
3 years ago
Line PQ in line RS intersect to form four right angles which statement that would it be
Sholpan [36]

Answer:

PQ is perpendicular to RS

that is to mean:

PQ⊥RS

Step-by-step explanation:

3 0
4 years ago
Referring to the Fig. in Question #40, find the unknown<br> length Y.
icang [17]

Answer:

tan30°=7/x

\frac{1}{ \sqrt{3} }  =  \frac{7}{x }  \\ x = 7 \sqrt{3}

cos30°=x/y

\frac{ \sqrt{3} }{2}   =  \frac{7 \sqrt{3} }{y}  \\  \\ 7 \sqrt{3}  \times 2 =  \sqrt{3}  \times y \\ \frac{7 \sqrt{3 }  \times 2}{ \sqrt{3} }  = y \\7 \times 2 = y \\ 14 = y

tell me if it's wrong.

7 0
2 years ago
Read 2 more answers
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