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2 years ago

What is the slope of this equation? y=8-x

Mathematics

1 answer:

Lostsunrise [7]2 years ago

5 0

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$y = 8 - x$

$y = - x + 8$

$y = - 1x + 8$

$Slope = coefficient \: \: of \: \: x$

Thus :

$Slope = - 1$

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This is so hard to me i need help <br> fast

Alexus [3.1K]

Answer:

1/3

Step-by-step explanation:

You can answer this as

9/27=1/3

and

3/9=1/3

and so 1/3 is the the constant proportionality for both figures

Hope You Understand :)

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1 year ago

Air has a density of 0.001226 g/mL. What volume of air would have a mass of 1.0 lb? A. 2.7 mL B. 815.6 mL C. 37 mL D. 3.7 × 102

Andre45 [30]

Answer:

$Volume = 3.7\ * 10^2\ L$

Step-by-step explanation:

Given

$Density = 0.001226 g/mL$

$Mass = 1.0\ lb$

Required

Determine the volume of air

Density is calculated using:

$Density = \frac{Mass}{Volume}$

Substitute values for Density and Mass

$0.001226 g/mL = \frac{1.0\ lb}{Volume}$

Convert lb to grams

$0.001226 g/mL = \frac{1.0 * 453.592\ g}{Volume}$

$0.001226 g/mL = \frac{453.592\ g}{Volume}$

Solve for Volume

$Volume = \frac{453.592\ g}{0.001226 g/mL}$

$Volume = 369977.161501\ mL$

Convert mL to L

$Volume = 369977.161501\ L * 0.001$

$Volume = 369.977161501\ L$

Represent using scientific notation

$Volume = 3.69977161501\ * 10^2\ L$

Approximate

$Volume = 3.7\ * 10^2\ L$

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2 years ago

7x-4y=20 for y when x=3

viktelen [127]

I think it is y=-.25
7*3 - 4y = 20
21 - 4y = 20
subtract 21 from each side
- 4y = - 1
divide each side by - 4
y= -.25

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3 years ago

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gayaneshka [121]

Answer:

27 3/32

Step-by-step explanation:

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2 years ago

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Your friend claims that it is possible to draw a right triangle where the cosine of either angle (theta) is exactly the same val

avanturin [10]

Answer:

B. No

$Cos \ \theta\neq Cos (90-\theta)\textdegree$

Step-by-step explanation:

-A right angle triangle has two complimentary acute angles and one right angle.

- $\theta$ is usually one of the acute angles and is equivalent to 90º minus it's complimentary acute angle.

-Complimentary angles add up to 90º.

#For complimentary angles:

$Sin \ \theta=Cos \ (90-\theta)\textdegree\\\\Cos \ \theta=Sin(90-\theta)\textdegree\\\\\therefore Cos \ \theta\neq Cos (90-\theta)\textdegree$

The two acute angles cannot have the same Cosine value.

Hence, she's not correct.

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2 years ago