All categories

3 years ago

How to find the vertex form of y=-2x^2+4

1 answer:

5 0

Y=−2(x+0)^2+4 this should be right

You might be interested in

I need this answer ?

FromTheMoon [43]

Are you sure you need help with that easy problem read it slowly then ask

7 0

3 years ago

How many factors does 144 have? i need it fast pleaseeee

Vedmedyk [2.9K]

1,2,3,4,6,8,9,12,16,18,24,36,48,72,144,

8 0

3 years ago

Read 2 more answers

In the right triangle, a = 20, b = 21. Find c A) 841 B) 22 C) 29

Mariulka [41]

Answer:

Step-by-step explanation:

3 0

2 years ago

Which of the following matrices is the solution matrix for the given system of equations? x + 5y = 11 x - y = 5

givi [52]

<h2>The required solution is x = 6 and y = 11 </h2>

Step-by-step explanation:

Given system of equations are

x+5y = 11 and x-y =5

$A= \left[\begin{array}{cc}1&5\\1&-1\end{array}\right]$ $X=\left[\begin{array}{c}x\\y\end{array}\right]$

and $B= \left[\begin{array}{c}11\\5\end{array}\right]$

∴AX=B

$adj A = \left[\begin{array}{cc}{-1}&{-5}\\{-1}&1\end{array}\right]$

$A= \left|\begin{array}{cc}1&5\\1&-1\end{array}\right|=-6$

∴ $A^{-1} =\frac{adj A}{|A|}$

So, $A^{-1} =\frac{ \left[\begin{array}{cc}{-1}&{-5}\\{-1}&1\end{array}\right]}{-6}$

$A^{-1} ={ \left[\begin{array}{c \c} {{\frac{1}{6} }}&{\frac{5}{6}}\ \\ {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]}$

$X =A^{-1}\times B$

⇒ $\left[\begin{array}{c}x\\y\end{array}\right] ={ \left[\begin{array}{c \c} {{\frac{1}{6} }}&{\frac{5}{6}}\ \\ {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]} \times \left[\begin{array}{c}11\\5\end{array}\right]$

⇒ $\left[\begin{array}{c}x\\y\end{array}\right] ={ \left[\begin{array}{c} {6}\\ {11} \end{array}\right]}$

∴ x= 6 and y = 11

The required solution is x = 6 and y = 11

7 0

2 years ago

Do these ratios form a proportion? $42 per 33 customers $28 per 22 customers yes no

Iteru [2.4K]

No I have to have a denomination

8 0

2 years ago

Read 2 more answers