The areas of the two parallelograms are 105 square inches and 20.997 square yards, respectively.
<h3>How to determine the area of a parallelogram</h3>
A parallelogram is a quadrilateral with two pairs of parallel sides with equal length and two pairs of angles of equal measure. The area of the parallelogram (<em>A</em>), in square yards or square inches, equals the product of its base length (<em>b</em>), in yards, and its height (<em>h</em>), in yards.
The area of each parallelogram is determined afterwards:
<h3>Exercise 10</h3>
<em>A = (10.5 in) · (10 in)</em>
<em>A = 105 in² </em>
<h3>Exercise 11</h3>
<em>A = (9 yd) · (2.333 yd) </em>
<em>A = 20.997 yd²</em>
The areas of the two parallelograms are 105 square inches and 20.997 square yards, respectively.
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Dude I hate to be a downer here but you want help for an entire page of homework for five points, you ain’t gonna get much help like that
A X A + B X B = (?)
Now what's the square route of (?)
I'm sorry haven't done this in a while. I'm sorry if I'm wrong.
Answer:
Sin(x+y)/sin(x-y) = [ sin (x + y) ]^2 / (cos y)^2 - (cos x)^2
Step-by-step explanation:
Sin(x+y)/sin(x-y) = [sin x cos y + cos x sin y]/ [sin x cos y - cos x sin y]
[sin x cos y + cos x sin y]/ [sin x cos y - cos x sin y]
multiply top and bottom of this fraction by [sin x cos y + cos x sin y]
the denominator becomes:
( sin x cos y)^2 - (cos x sin y)^2
(sin y)^2 = 1 - (cos y)^2
( sin x cos y)^2 - (cos x sin y)^2
= ( sin x cos y)^2 - (cos x)^2 [ 1 - (cos y)^2 ]
= ( 1 - (cos x)^2) (cos y)^2 - (cos x)^2 [ 1 - (cos y)^2 ]
= (cos y)^2 - ((cos x)^2) (cos y)^2 - (cos x)^2 + [(cos x)^2] (cos y)^2
things cancel out
= (cos y)^2 - (cos x)^2
Sin(x+y)/sin(x-y) = [ sin (x + y) ]^2 / (cos y)^2 - (cos x)^2
Answer: X-axis
Step-by-step explanation: You can use the "Desmos Graphing Calculator".