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3 years ago

What is the value of x?

Mathematics

2 answers:

Setler [38]3 years ago

8 0

Answer: The horizontal value in a pair of coordinates how far along the point is. The X Coordinate is always written first in an ordered pair of coordinate (x,y), such as (12, 5).

Step-by-step explanation: Hope This Helps :)

For a example, the value 12 is the X coordinate. And Also called Abscissa.

3241004551 [841]3 years ago

5 0

The letter "x" is often used in algebra to mean a value that is not yet known. It is called a "variable" or sometimes an "unknown".

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The Middle School girls’ soccer team won 75% of its games this season. If the team won 15 games, how many games did it play?

Monica [59]

The soccer team won 20 games

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3 years ago

. 5.8x10 to the power of 7

Delvig [45]

PEMDAS means we do exponents before we multiply.

10 ^ 7 = 10,000,000

(10 * 10 * 10 * 10 * 10 * 10 * 10)

5.8 * 10,000,000

= 58,000,000

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3 years ago

Find 10th term of a geometric sequence whose first two terms are 2 and -8. Please answer!!

Shalnov [3]

Answer:

The 10th term is -524,288

Step-by-step explanation:

The general format of a geometric sequence is:

$a_{n} = r*a_{n-1}$

In which r is the common ratio and $a_{n+1}$ is the previous term.

We can also use the following equation:

$a_{n} = a_{1}*r^{n-1}$

In which $a_{1}$ is the first term.

The common ratio of a geometric sequence is the division of the term $a_{n+1}$ by the term $a_{n}$

In this question:

$a_{1} = 2, a_{2} = -8, r = \frac{-8}{2} = -4$

10th term:

$a_{10} = 2*(-4)^{10-1} = -524288$

The 10th term is -524,288

6 0

3 years ago

the perimeter of a parrallelogram is 72 meters. The width of the parallelogram is 4 meters less than its length. Find the length

Papessa [141]

L+L+(L-4)+(L-4)=72

4L-8=72
4L=80
L= 20

so W= 20-4 or 16

7 0

3 years ago

The orbital period, P, of a planet and the planet’s distance from the sun, a, in astronomical units is related by the formula P=

Elodia [21]

Answer: 9.54731702 astronomical units

Step-by-step explanation:

Given: The orbital period, P, of a planet and the planet’s distance from the sun, a, in astronomical units is related by the formula $P=a^{\frac{3}{2}$ .

Saturn’s orbital period P = 29.5 years

Substitute this value in the equation above, we get

$29.5=a^{\frac{3}{2}}\\\Rightarrow(29.5)^{\frac{2}{3}}=a\\\Rightarrow\ a=9.54731702\text{ astronomical units}$

Hence, its distance from the sun = 9.54731702 astronomical units.

3 0

3 years ago

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