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3 years ago

What happens to the volume of a rectangular prism when the length and width are double and the height is tripled

Mathematics

1 answer:

Andrei [34K]3 years ago

3 0

The volume goes up by a factor of 2 * 2 * 3 = 12 times.

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PLEASE HELP!!!<br> In the diagram below, if m1 = 79, find the<br> measure of each numbered angle.

Reika [66]

2 - 101
3 - 101
4 - 79
5 - 79
6 - 101
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3 0

3 years ago

L need help with this

soldi70 [24.7K]

Answer:

$24.11

Step-by-step explanation:

Let the cost of the present be c.

Then (3/4)c = $18.33.

To isolate (solve for) c, mult. both sides of this equation by (4/3):

(4/3)(3/4)c = (4/3)($18.33), or

c = $24.11

5 0

3 years ago

Estimate the Value Of Each Expression to the nearest integer .

omeli [17]

Answer:

see below

Step-by-step explanation:

14. We can represent 1 as √1 and 2 as √4 and because 1 < 3 < 4, we know that √3 is in between 1 and 2. However, 3 is closer to 4 than it is to 1 so √3 is about 2.

15. Again, 3 is √9 and 4 is √16. 9 < 10 < 16 so √10 is in between 3 and 4, however, since 10 is closer to 9 as it is to 16, we know that √10 is about 3.

16. -4 = -√16 and -5 = -√25, since 16 < 22 < 25, we know that -√22 is in between -4 and -5 but 22 is closer to 25 so the answer is -5.

17. -10 = -√100 and -11 = -√121 so -√120 is in between -10 and -11. Since 120 is closer to 121, the answer is -11.

5 0

3 years ago

A catering service offers 5 appetizers,4 main courses, and 8 desserts. A customer is to select 4 appetizers,2 main courses,and 3

Alisiya [41]

Answer:

468 ways

Step-by-step explanation:

Given: A catering service offers 5 appetizers, 4 main courses, and 8 desserts

To find: number of ways a customer is to select 4 appetizers, 2 main courses,and 3 desserts.

Solution:

A permutation is an arrangement of elements such that order of elements matters and repetition is not allowed.

Number of appetizers = 5

Number of main courses = 4

Number of desserts = 8

Number of ways of choosing k terms from n terms = $nPk=\frac{n!}{(n-k)!}$

Number of ways a customer is to select 4 appetizers, 2 main courses,and 3 desserts = $5P4+4P2+8P3$

$=\frac{5!}{(5-4)!}+\frac{4!}{(4-2)!}+\frac{81}{(8-3)!}\\=5!+\frac{4!}{2!}+\frac{8!}{5!}\\=5!+(4\times 3)+(8\times 7\times 6)\\=120+12+336\\=468$

So, this can be done in 468 ways.

7 0

3 years ago

Which of the following systems of inequalities represent the graph?

Oduvanchick [21]

The answer to your question is 2 and 4.

8 0

4 years ago