$a_{n} \: = \: 2(a_{n - 1})^{2} \\ a_{1} = 4 \: (given) \\ a_{2} = \: 2(a_{2 - 1})^{2} \\ = 2(a_{ 1})^{2} \\ = 2 \times {4}^{2} \\ = 32 \\ \\ a_{3} = \: 2(a_{3 - 1})^{2} \\ = 2(a_{ 2})^{2} \\ = 2 \times {32}^{2} \\ = 2 \times 1024 \\ = 2048$

so first 3 terms are

4, 32, 2048

8 0

3 years ago

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Given the function ƒ(x ) = 3x + 1, evaluate ƒ(a + 1).

Setler79 [48]

Answer:

$\Huge \boxed{3a+4}$

Step-by-step explanation:

The function is given.

$f(x)=3x+1$

To find : $f(a+1)$

The input for the function f(x) is (a + 1).

Replace x with (a + 1).

$f(a+1)=3(a+1)+1$

Expand brackets.

$f(a+1)=3a+3+1$

Simplifying.

$f(a+1)=3a+4$

3 0

3 years ago

How do you do this? is geometry please help this define my grade

ella [17]

Answer:

x = 21.287

Step-by-step explanation:

Use:

SOH CAH TOA

Cos(37) = 17.3/x

x = 21.287

7 0

2 years ago

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