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2 years ago

6

Maggie bought trains for her model train set. She spent $99. Gage bought some trains too. He spent $66. Each train cost the same

amount. t most how much could each train cost?

1 answer:

BartSMP [9]2 years ago

3 0

At most each train could cost $33

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I need to know what the answer is for this question

Anna35 [415]

3pm to 7pm is 4 hours. 4 hours times 2 degrees dropped every hour is 8 degrees total dropped within those 4 hours. The previous temperature of 4 degrees at 3pm minus the 8 degres dropped is -4.

Answer is D.

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2 years ago

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For f(x) = 3x^2 + 2x - 1, identify the rule for g(x) = f(x + 1) - 6 and it's graph.

PilotLPTM [1.2K]

2x2 + x −#6 _____________

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(2x − 3)(x + 2) __

(x + 1)(x − 1) ∙ (x + 1)(x + 1) __ (x + 2)(x − 2) Factor the numerator and denominator.

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(2x − 3)(x + 1) __ (x − 1)(x − 2)

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3 years ago

Can someone solve these 2 problems ? 9 and 8

siniylev [52]

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2 years ago

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Identifying Possible Triangles

Masja [62]

Answer:

3rd triangle can be constructed with dimensions 2,6,7.

Step-by-step explanation:

sum of any two sides > third side.

difference of any two sides < third side

1.

8+5=13 not >14 (no triangle.)

2.

7+8=15 not >15 (no triangle)

3.

2+6=8>7

2+7=9>6

7+6=13>2

7-2=5<6

7-6=1<2

6-2=4<7

so it is a triangle.

4.

6+3=9 not >10 (not a triangle)

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2 years ago

How do you do this. Please give a full answer and explain why.

OverLord2011 [107]

<u>L</u><u>a</u><u>w</u><u> </u><u>o</u><u>f</u><u> </u><u>E</u><u>x</u><u>p</u><u>o</u><u>n</u><u>e</u><u>n</u><u>t</u>

$\displaystyle \large{ {a}^{ - n} = \frac{1}{ {a}^{n} } }$

Compare the terms.

$\displaystyle \large{ {a}^{ - n} = {( - 2)}^{ - 3} }$

Therefore, a = -2 and n = 3. From the law of exponent above, we receive:

$\displaystyle \large{ {( - 2)}^{ - 3} = \frac{1}{ {( - 2)}^{ 3} } }$

<u>E</u><u>x</u><u>p</u><u>o</u><u>n</u><u>e</u><u>n</u><u>t</u><u> </u><u>D</u><u>e</u><u>f</u><u>.</u> (For cubic)

$\displaystyle \large{ {a}^{3} = a \times a \times a }$

Factor (-2)^3 out.

$\displaystyle \large{ {( - 2)}^{ - 3} = \frac{1}{( - 2) \times ( - 2) \times ( - 2)}}$

(-2) • (-2) = 4 | Negative × Negative = Positive.

$\displaystyle \large{ {( - 2)}^{ - 3} = \frac{1}{4 \times ( - 2)}}$

4 • (-2) = -8 | Negative Multiply Positive = Negative.

$\displaystyle \large{ {( - 2)}^{ - 3} = \frac{1}{ - 8}}$

If either denominator or numerator is in negative, it is the best to write in the middle or between numerator and denominators.

Hence,

$\displaystyle \large \boxed{ {( - 2)}^{ - 3} = - \frac{1}{ 8}}$

The answer is - 1 / 8

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2 years ago