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spayn [35]
3 years ago
11

What is lm in the triangle at the right​

Mathematics
1 answer:
Paha777 [63]3 years ago
7 0

There is no file attached it is blank can’t help you if I can’t see what i am suppose to be doing

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One side of a triangle is 6 cm shorter than the base, x. The other side is 4 cm longer than the base. What lengths of the base w
xeze [42]
X= base
one side= x-6
other side= 4+x

x+x-6+4+x = 43

3x=43+2

x=15 length of base
7 0
4 years ago
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The area of the shaded region
lbvjy [14]

Answer:

27.74cm^2

Step-by-step explanation:

area of circle: 3 times 3 times pi = 28.26cm^2

area of square: 8 times 7 = 56cm^2

subtract area of circle from square

56-28.26=27.74cm^2

4 0
4 years ago
Emma invested $750 in an account paying an interest rate of 1.9% compounded quarterly. Assuming no deposits or withdrawals are m
storchak [24]

Answer:

10.2

Step-by-step explanation:

3 0
3 years ago
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Assignment: Organizing the Build Investigation
pentagon [3]

The first step to solving this problem is to decide the best approach to organizing the Nuts and Screws.

I personally would start by separating both groups, this way it becomes easier to know roughly where to look to find what you need. After doing this it would make sense to simply place the bigger Nuts with the bigger Nuts and the bigger screws with the bigger screws, which would leave you with 4 separate groups. The 2 nut groups would be on one side and the 2 screw groups would be on the side.

Now for the number line, I have included the decimal numbers in order down below, we will start with the smallest fraction and begin to plot the points.

*I have also included my graph that I drew on Desmos as well down below*

And now by using everything I have given you the answer to the last question becomes clear ;-) :

4 Screws 1/16” x 3” long

6 Screws 11/64” x 4” long

16 Screws 3/8” x 2” long

1 Screw 7/16” x 3” long

12 Screws 5/64” x 3” long

3 Screws 3/32” x 4” long

1 Screw 1/2” x 3” long

1 Screw 3/4” x 2” long

4 Hex bolts 1.5” x 4” long

DSMT4 4 Hex bolts 1 7/8” x 4” long

1 Hex bolt 2.25” x 2” long

4 Hex bolts 3.75” x 3” long

6 Hex bolts 3 3/8” x 3” long

If you find out that my answer is wrong just let me know, and I guarantee that I will come back and rework my math :-)

Ps. By rating people and giving people Brainliest you not only make them feel good but you get 25% of the points you spent back :-)

6 0
3 years ago
The height meters of a mass projected vertically upwards at a time seconds s=ut-0.5gt².
Sergeu [11.5K]

9514 1404 393

Answer:

  t ≈ 0.590 s (ascent); 5.532 s (descent)

Step-by-step explanation:

We are interested in the values of t when s=16.

  s = 30t -4.9t²

  4.9t^2 -30t +16 = 0 . . . . . substitute 16 for s; put in standard form

The quadratic formula can be used to find the solutions:

  t = (-(-30) ±√((-30)² -4(4.9)(16)))/(2(4.9))

  t = (30 ±√586.4)/9.8 ≈ 0.59023, 5.53221 . . . . seconds after launch

a) It will take 0.590 seconds to reach 16 m height initially.

b) It will take 5.532 seconds to return to 16 m height on descent.

3 0
3 years ago
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