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4 years ago

Give an example of a repeating decimal where two digits repeat

Mathematics

2 answers:

coldgirl [10]4 years ago

4 0

Answer: 0.36363636...

Step-by-step explanation: A repeating decimal is a non-terminating or non-ending decimal in which one or more of the digits repeat.

So in this example, 0.36363636... is a repeating decimal because the 36 repeats. To indicate that we have a repeating decimal, we put a bar over the digit or group of digits that repeat.

Novay_Z [31]4 years ago

3 0

27.33333333 I hope it helps!

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Cars arrive at the Wendy's drive-through at a rate of 1 car every 5 minutes between the hours of 11:00 PM and 1:00 AM. on Saturd

mestny [16]

Answer:

1) $P(X = 8) = 0.1033$

$P(X = 9) = 0.0688$

2) Expected number of 200 restaurants in which exactly 8 customers use the drive-through: 20.66

Expected number of 200 restaurants in which exactly 9 customers use the drive-through: 13.76

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

$e = 2.71828$ is the Euler number

$\mu$ is the mean in the given time interval.

Question 1. Use the Poisson distribution to calculate the probability that exactly 8 cars will use the drive-through between 12:00 midnight and 12:30 AM on a Saturday night at Wendy's. Do the same for exactly 9 cars.

Cars arrive at the Wendy's drive-through at a rate of 1 car every 5 minutes between the hours of 11:00 PM and 1:00 AM. on Saturday nights. This means that during 30 minutes, 6 cars expected to arrive. So $\mu = 6$ .

P(X = 8)

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 8) = \frac{e^{-6}*(6)^{8}}{(8)!} = 0.1033$

P(X = 9)

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 9) = \frac{e^{-6}*(6)^{9}}{(9)!} = 0.0688$

Question 2. At how many of the 200 restaurants in the survey would you expect exactly 8 customers to use the drive-through? exactly 9 customers?

There is a 10.33 probability that 8 customers would use the drive through for each restaurant.

So of 200, the expected number is

$E(X) = 200*0.1033 = 20.66$

There is a 6.88 probability that 9 customers would use the drive through for each restaurant.

So of 200, the expected number is

$E(X) = 200*0.0688 = 13.76$

8 0

3 years ago

Write 0.132 as a number

Luden [163]

0.132 written in lowercase:

one hundred thirty-two thousandths

zero point one hundred thirty-two

or, even simpler:

zero point one three two

4 0

3 years ago

Read 2 more answers

Part 1 of 2

gogolik [260]

Answer:

The error is when 6y = 12 it will be -6y = 12 and the intercept would be -2.

Step-by-step explanation:

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1 year ago

Find the value of x that makes m

Sindrei [870]

Answer:

X = 20

Step-by-step explanation:

Hope this helps! If you need the explanation, let me know. Pls give brainliest!

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2 years ago

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When Raphael solved the system below by using the method of elimination, he changed the second equation to -8x-2y=-2 what proper

galben [10]

For this case, what we are going to do is use the following property:
Multiply an equation by a scalar.
In this case, the scalar will be:
k = -2
We have then that equation 2 will be:
k * (4x + y) = k * 1
-2 * (4x + y) = - 2 * 1
-8x-2y = -2
Answer:
The property that justifies this manipulation is:
Multiply an equation by a scalar.

4 0

3 years ago