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prisoha [69]
3 years ago
10

Give an example of a repeating decimal where two digits repeat

Mathematics
2 answers:
coldgirl [10]3 years ago
4 0

Answer: 0.36363636...

Step-by-step explanation: A repeating decimal is a non-terminating or non-ending decimal in which one or more of the digits repeat.

So in this example, 0.36363636... is a repeating decimal because the 36 repeats. To indicate that we have a repeating decimal, we put a bar over the digit or group of digits that repeat.

Novay_Z [31]3 years ago
3 0
27.33333333 I hope it helps!
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Radius: 3.5 units, Center (0,3.5)
vlabodo [156]

Step-by-step explanation:

General equation of circle:

(x - a)² + (y - b)² = r².

Therefore we have x² + (y - 3.5)² = 12.25.

5 0
2 years ago
Find the mean of the data in the bar chart below.
Snowcat [4.5K]
<h2>Answer:</h2>

12

<h2>Step-by-step explanation:</h2>

<u><em>The mean is also the average.</em></u>

Add up all the number of students all together:

12+13+14+9

48

Now, Divide the total amount of students (48) by the amount of numbers you added (in this case, 48/4 because we added 4 numbers wich are 12+13+14+9)

The average amount of students is 12

7 0
2 years ago
HELP! 8TH GRADE MATH PLS LOL
LekaFEV [45]
<h2><u>Given</u><u>:</u><u>-</u></h2>

{ \large{➢ \:  \:  \bf{x =  - 8}}}

<h2><u>Solution</u><u>:</u><u>-</u></h2>

{ \large{➢ \:  \:  \bf{ \dfrac{2y}{3}  = 3 \times  - 8 + 34}}}

{ \large{➢ \:  \:  \bf{ \dfrac{2y}{3}  =  - 24 + 34}}}

{ \large{ \bf{ ➢ \:  \: \cancel{2}y = 3 \times { \cancel{(10)} {} \:  \:  ^{5} }}}}

{ \large{ \therefore{  \bf{y = 15 \:  \: Ans.}}}}

3 0
3 years ago
Whats x? i don’t understand
rewona [7]

Answer:

The letter "x" is often used in algebra to mean a value that is not yet known. It is called a "variable" or sometimes an "unknown". In x + 2 = 7, x is a variable, but we can work out its value if we try! A variable doesn't have to be "x", it could be "y", "w" or any letter, name or symbol. See: Variable.

Step-by-step explanation:

8 0
3 years ago
PLZ HELP MARKIN BRAINIEST!!!
Dahasolnce [82]

From the graph, when x = 1, y = 57,000.

Replace x with 1 in the equations and see if any of the Y 's equal 57,000 :

y = -2610.82(1) + 47860.82 = 45,250

y = 219(1)^2 - 6,506.78(1) + 59,385 = 219 - 6506.78 + 59385 = 53,097.22

y = 54041.5(0.9)^1 =  48,637.35

y = 10,504.6 (1.1)^1 = 11,555.06

The second equation is the closest. so try another x value to see if it is close to the Y value:

Let's try x = 14:

y = 219(14)^2 - 6506.78(14) + 59,385 = 42924 - 91094.92 + 59385 = 11,214.08

This is close to Y = 12,00 shown on the graph

SO the closest equitation is y = 219x^2 - 6506.78x + 59385

8 0
3 years ago
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