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3 years ago

Give an example of a repeating decimal where two digits repeat

Mathematics

2 answers:

coldgirl [10]3 years ago

4 0

Answer: 0.36363636...

Step-by-step explanation: A repeating decimal is a non-terminating or non-ending decimal in which one or more of the digits repeat.

So in this example, 0.36363636... is a repeating decimal because the 36 repeats. To indicate that we have a repeating decimal, we put a bar over the digit or group of digits that repeat.

Novay_Z [31]3 years ago

3 0

27.33333333 I hope it helps!

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melomori [17]

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3 years ago

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aalyn [17]

Answer:

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3 years ago

What is 169.56 rounded to the nearest hundredths?

dedylja [7]

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2 years ago

Differentiate the following functions (x^3+1)(x-2)÷x^2

Masja [62]

Given:

The given function is:

$\dfrac{(x^3+1)(x-2)}{x^2}$

To find:

The differentiation of the given function.

Solution:

Consider the given function,

$y=\dfrac{(x^3+1)(x-2)}{x^2}$

It can be written as:

$y=\dfrac{(x^3)(x)+(x^3)(-2)+(1)(x)+(1)(-2)}{x^2}$

$y=\dfrac{x^4-2x^3+x-2}{x^2}$

$y=\dfrac{x^4}{x^2}-\dfrac{2x^3}{x^2}+\dfrac{x}{x^2}-\dfrac{2}{x^2}$

$y=x^2-2x+\dfrac{1}{x}-\dfrac{2}{x^2}$

Differentiate with respect to x.

$y'=\dfrac{d}{dx}(x^2)-\dfrac{d}{dx}(2x)+\dfrac{d}{dx}(x^{-1})-\dfrac{d}{dx}\2(x^{-2})$

$y'=2x-2(1)+(-x^{-2})-2(-2x^{-3})$

$y'=2x-2-\dfrac{1}{x^2}+\dfrac{4}{x^3}$

Therefore, the differentiation of the given function is $2x-2-\dfrac{1}{x^2}+\dfrac{4}{x^3}$ .

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3 years ago

The student council set a goal of raising at least $500 in flower sales. So far it has raised $415.

zzz [600]

Hi There!

Ok, so student council needs 500 dollars from flower sale, and they already have 415, To find how much they need you have to subtract 500-415, your final answer should be 85, so the student council needs $85 dollars more to reach their goal.

Hope This Helps :)

6 0

2 years ago

Read 2 more answers