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Lorico [155]
3 years ago
14

3x3 + 3 x 1 = 3 x (3 +O)

Mathematics
1 answer:
Shkiper50 [21]3 years ago
6 0

Answer:

9+3=9

12 is not equal to 9

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Brums [2.3K]

Answer:

169 sq cm

Step-by-step explanation:

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3 years ago
PLEASE HELP ME!!!!!!!
Viefleur [7K]

Answer:

Step-by-step explanation:

x^2 + 2x = 6x+45

x^2 -4x -45 =0

x^2 - 5x +9x -45 =0

x(x-5) +9 (x-5)=0

(x-5)(x+9)=0

x = 5, -9

x = 5; measure of exterior angle = 5^2+2(5) = 35

x=-9; measure of exterior angle  = (-9)^2 + 2(-9) = 63

5 0
3 years ago
What is the estimate of 256+321
Sati [7]
The estimate would be 2+3 5+2 and 6+1 so 577 you can also just round and do 250 +300= 550 +20=570
6 0
3 years ago
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Problem:
Molodets [167]

Answer:

a)

We know that:

a, b > 0

a < b

With this, we want to prove that a^2 < b^2

Well, we start with:

a < b

If we multiply both sides by a, we get:

a*a < b*a

a^2 < b*a

now let's go back to the initial inequality.

a < b

if we now multiply both sides by b, we get:

a*b < b*b

a*b < b^2

Then we have the two inequalities:

a^2 < b*a

a*b < b^2

a*b = b*a

Then we can rewrite this as:

a^2 < b*a < b^2

This means that:

a^2 < b^2

b) Now we know that a.b > 0, and a^2 < b^2

With this, we want to prove that a < b

So let's start with:

a^2 < b^2

only with this, we can know that a*b will be between these two numbers.

Then:

a^2 < a*b < b^2

Now just divide all the sides by a or b.

if we divide all of them by a, we get:

a^2/a < a*b/a < b^2/a

a < b < b^2/a

In the first part, we have a < b, this is what we wanted to get.

Another way can be:

a^2 < b^2

divide both sides by a^2

1 < b^2/a^2

Let's apply the square root in both sides:

√1 < √( b^2/a^2)

1 < b/a

Now we multiply both sides by a:

a < b

7 0
3 years ago
The sum of three numbers is 10
sashaice [31]
A possible equation is 3+2+5
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3 years ago
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