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ololo11 [35]
4 years ago
6

Write the standard form of the line that passes through the given points. Include your work in your final answer. Type your answ

er in the box provided or use the upload option to submit your solution.
(-3, 5) and (-2, -6)
Mathematics
1 answer:
romanna [79]4 years ago
5 0

Answer:

11x+y = -28

Step-by-step explanation:

We have two points so we can find the slope

m = (y2-y2)/(x2-x1)

   = (-6-5)/ (-2--3)

   = -11(-2+3)

   = -11/1

The slope is -11

We can use point slope to make an equation

y-y1 = m (x-x1)

y-5 = -11(x--3)

y -5 = -11(x+3)

Distribute

y-5 = -11x-33

Add 5 to each side

y-5+5 = -11x-33+5

y = -11x-28

Add 11x to each side

11x+y = -11x+11x-28

11x+y = -28

This is the standard form of a line

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Step-by-step explanation:

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Answer:

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3 years ago
I'm having trouble finding the answer
Tamiku [17]
16) you are right
3x-4=2x+6
x=10

17)
1st segment = x
2nd segment = 2x
3d segment = 4x+3
equation x+2x+4x+3=38
7x = 38-3
7x=35
x=5
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SpyIntel [72]

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Step-by-step explanation:

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Read 2 more answers
What is the measure of an exterior angle of a regular 13-sided polygon?
Mariulka [41]
\bf \textit{sum of all exterior angles in a polygon}\\\\
n\theta =360\quad 
\begin{cases}
n=\textit{number of sides}\\
\theta =\textit{angle in degrees}\\
----------\\
n=13
\end{cases}\implies 13\theta =360\implies 
\theta =\cfrac{360}{13}
6 0
4 years ago
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